使用php语言的array_merge函数时,以为相同的键名会覆盖,但是请看如下代码:
$a1 = array(1=>'abc', 3=>10);
$a2 = array(1=>'efg', 3=>20);
print_r(array_merge($a1, $a2));
会输出什么?我们预想中的是:
Array
(
[1] => efg
[3] => 20
)
实际上输出的是:
Array
(
[0] => abc
[1] => 10
[2] => efg
[3] => 20
)
不但没有被覆盖,而且数字键被重新连续索引了。
起初以为这个是bug,后来翻了php手册 http://php.net/manual/zh/function.array-merge.php
「如果输入的数组中有相同的字符串键名,则该键名后面的值将覆盖前一个值。然而,如果数组包含数字键名,后面的值将不会覆盖原来的值,而是附加到后面。
如果只给了一个数组并且该数组是数字索引的,则键名会以连续方式重新索引。」

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