本文实例讲述了php实现猴子选大王问题算法。分享给大家供大家参考。具体分析如下:
一、问题:
n只猴子围坐成一个圈,按顺时针方向从1到n编号。
然后从1号猴子开始沿顺时针方向从1开始报数,报到m的猴子出局,再从刚出局猴子的下一个位置重新开始报数,
如此重复,直至剩下一个猴子,它就是大王。
设计并编写程序,实现如下功能:
(1) 要求由用户输入开始时的猴子数$n、报数的最后一个数$m。
(2) 给出当选猴王的初始编号。
二、解决方法:
/** * @param int $n 开始时的猴子数量 * @param int $m 报道的最后一个数 *(报到这个数的猴子被淘汰,然后下一个猴子重新从①开始报数) * @return int 猴子的初始编号 */ function monkeySelectKing($n,$m) { //猴子的初始数量不能小于2 if ($n<2) { return false; } $arr=range(1,$n); //将猴子分到一个数组里, 数组的值对应猴子的初始编号 $unsetNum=0; //定义一个变量,记录猴子的报数 for ($i = 2; $i <=$n*$m ; $i++) //总的循环次数不知道怎么计算, { //不过因为循环中设置了return,所以$m*$len效率还可以 foreach ($arr as $k => $v) { $unsetNum++; //每到一个猴子, 猴子报数+1 //当猴子的报数等于淘汰的数字时:淘汰猴子(删除数组元素) //报数归0(下一个猴子从1开始数) if ($unsetNum==$m) { // echo "<pre class="brush:php;toolbar:false">";//打开注释,可以看到具体的淘汰过程 // print_r($arr); unset($arr[$k]); //淘汰猴子 $unsetNum=0; //报数归零 if (count($arr)==1) //判断数组的长度, 如果只剩一个猴子, 返回它的值 { return reset($arr); } } } } } var_dump(monkeySelectKing(6, 3));
补充改进算法(该算法更加简洁明了!):
function yuesefu($n,$m) { $r=0; for($i=2; $i<=$n; $i++) { $r=($r+$m)%$i; } return $r+1; } print_r(yuesefu(3,3));
希望本文所述对大家的php程序算法设计有所帮助。

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