PHP query operation to implement voting function

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PHP query operation to implement voting function_php skills

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May 16, 2016 pm 07:52 PM

phpvoteInquire

The example in this article shares the code for php query operation to implement the voting function for your reference. The specific content is as follows

Title:

Summary of problem-solving methods:

Method 1:
1. Main voting page:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>投票</title>
<style>
#list
{
  width:400px;
  height:300px;}
#jieguo
{
  width:400px;
  height:300px;}
.x
{
   
  float:left;}
 
</style>
</head>
 
<body>
 
<form action="TouChuLi.php" method="post">
<&#63;php
include ("DBDA.class.php");
$db=new DBDA();
//从调研题目表中找出题目代号和名称
$sql="select * from diaoyantimu limit 0,1";
$arr=$db->query($sql);
$tmmc=$arr[0][1];
$tmdh=$arr[0][0];
echo "<div><h2 id="tmmc">{$tmmc}:</h2></div>";
//从调研选项表中输出选项内容：
$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$tmdh}'";
$arrxx=$db->query($sqlxx);
echo "<div id='list'>";
foreach ($arrxx as $v)
{
  echo "<div><input type='checkbox' value='{$v[0]}' name='xx[]'>{$v[1]}</div><br />";
}
 
&#63;>
<input type="submit" value="提交">
<input type="button" value="查看结果" id="check" onclick="Showjieguo()">
</form>
</div>
 
<div id="jieguo" style="display:none">
<&#63;php
//计算总人数：
$sqlzs="select sum(numbers) from diaoyanxuanxiang where timudaihao='{$tmdh}'";
$zrs=$db->query($sqlzs);
 
foreach ($arrxx as $v)
{
   
  $name=$v[1];
  $number=$v[2];
  if($zrs[0][0]==0)
   {
     $bfb = 0;
   }
   else
   {
     $bfb = ($number/$zrs[0][0])*100;
   }
  $bfb=round($bfb,2);
  echo "<div>
    <span class='x'>{$name} </span>
    <div class='x' style='width:200px; height:10px; background-color:#808080'>
    <div style='width:{$bfb}%; height:10px; background-color:#FF8040'> </div>
    </div>
    <span class='x'>{$number} </span>
    <span class='x'>{$bfb}% </span>
    </div>
    <br />
    "; 
}
&#63;>
<input type="button" value="返回" id="fanhui" onclick="Showfanhui()">
</div>
<script>
function Showjieguo()
{
  document.getElementById("list").style.display="none";
  document.getElementById("jieguo").style.display="block";
  }
function Showfanhui()
{
  document.getElementById("list").style.display="block";
  document.getElementById("jieguo").style.display="none";
  }
</script>
 
</body>
</html>

2. Process voting page:

<&#63;php
$arr=$_POST["xx"];
include ("../DBDA.class.php");
$db=new DBDA();
 
 
foreach($arr as $v)
{
  $sql = "update diaoyanxuanxiang set numbers = numbers+1 where ids = '{$v}'";
  $db->Query($sql,1);//1代表$sql的类型
}
header ("location:TouPiao.php");
&#63;>

3. Create a class for accessing the database and encapsulate it for reference:

<&#63;php
//执行一个sql语句，返回相应的结果
class DBDA
{
  public $host="localhost";//数据库服务器地址
  public $uid="root";//数据库用户名
  public $password="";//数据库密码
  //执行SQL语句的方法
  //参数里面：$sql代表要执行的sql语句；$type是sql语句的类型，0代表查询，1代表其他(增删改)；$db代表要操作的数据库
  function Query($sql,$type=0,$db="mydb")
  {
    //造连接对象
    $dbconnect=new MySQLi($this->host,$this->uid,$this->password,$db);
    //判断连接是否出错
    !mysqli_connect_error() or die("连接失败！");
    //执行sql语句
    $result=$dbconnect->query($sql);
    //判断SQL语句类型
    if($type==0)
    {
       //如果是查询语句返回结果集的二维数组
      return $result->fetch_all();
      }
    else
    {
      //如果是其他语句，返回true或false
      return $result;
      }   
    }
     
  }

Method 2:

1. Main voting page:

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>投票</title>
<style>
.x
{
   
  float:left;}
 
</style>
</head>
 
<body>
 
<form action="TouChuLi.php" method="post">
<&#63;php
include ("../DBDA.class.php");
$db=new DBDA();
//从调研题目表中找出题目代号和名称
$sql="select * from diaoyantimu limit 0,1";
$arr=$db->query($sql);
$tmmc=$arr[0][1];
$tmdh=$arr[0][0];
echo "<div><h2 id="tmmc">{$tmmc}:</h2></div>";
//从调研选项表中输出选项内容：
$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$tmdh}'";
$arrxx=$db->query($sqlxx);
echo "<div id='list'>";
foreach ($arrxx as $v)
{
  echo "<div><input type='checkbox' value='{$v[0]}' name='xx[]'>{$v[1]}</div><br />";
}
 
&#63;>
<input type="submit" value="提交">
<a href="ChaKan.php"><input type="button" value="查看结果" id="check" ></a>
</form>
</body>
</html>

2. Process voting page:

<&#63;php
$arr=$_POST["xx"];
include ("../DBDA.class.php");
$db=new DBDA();
 
 
foreach($arr as $v)
{
  $sql = "update diaoyanxuanxiang set numbers = numbers+1 where ids = '{$v}'";
  $db->Query($sql,1);//1代表$sql的类型
}
header ("location:TouPiao.php");
&#63;>

3. View the voting results page:

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>查看结果</title>
<style>
.x
{
  float:left;}
</style>
</head>
<body>
 
<&#63;php
include ("../DBDA.class.php");
$db=new DBDA();
//从调研题目表中找出题目代号和名称
$sql="select * from diaoyantimu limit 0,1";
$arr=$db->query($sql);
$tmmc=$arr[0][1];
echo "<div><h2 id="tmmc">{$tmmc}:</h2></div>";
//从调研选项表中输出选项内容：
$sqlxx="select * from diaoyanxuanxiang where timudaihao='{$arr[0][0]}'";
$arrxx=$db->query($sqlxx);
 
//计算总人数：
$sqlzs="select sum(numbers) from diaoyanxuanxiang where timudaihao='{$arr[0][0]}'";
$zrs=$db->query($sqlzs);
 
foreach ($arrxx as $v)
{
   $name=$v[1];//调研项目名称
   $number=$v[2];//选择该项的人数
   //判断总人数是否为0
   if($zrs[0][0]==0)
   {
     $bfb = 0;
   }
   else
   {
     $bfb = ($number/$zrs[0][0])*100;//求百分比
   }
   
  $bfb=round($bfb,2); //取小数点后两位
  echo "<div>
  <span class='x'>{$name} </span>
  <div class='x' style='width:200px; height:10px; background-color:#808080'>
  <div style='width:{$bfb}%; height:10px; background-color:#FF8040'> </div>
  </div>
  <span class='x'>{$number} </span>
  <span class='x'>{$bfb}%</span><br />
  </div><br />"; 
}
&#63;>
<br />
<a href="TouPiao.php"><input type="button" value="返回"></a>
</body>
</html>

Display results:

The above is the entire content of this article. I hope it will be helpful to everyone in learning PHP programming.

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