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正则截取html中的一段

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Jun 23, 2016 pm 02:38 PM

<html><body>..................<ul class="style5"><li><a href="/profiles/83291221"><img src="/static/imghwm/default1.png"  data-src="/images/252754752"  class="lazy"   alt="标题标题" />标题标题</a></li><li><a href="/profiles/83291221"><img src="/static/imghwm/default1.png"  data-src="/images/252754752"  class="lazy"   alt="标题标题" />标题标题</a></li><li><a href="/profiles/83291221"><img src="/static/imghwm/default1.png"  data-src="/images/252754752"  class="lazy"   alt="标题标题" />标题标题</a></li></ul>................</body></html>

这样的循环我要截取第一条,多的不要

标题标题

中的"83291221" "标题标题" 这两个,另外把这两个转换成变量求大神解@@@

回复讨论(解决方案)

preg_match_all("|<li><a href=[\"\']\/(.*)\/(.*)[\"\']><img (.*) alt="正则截取html中的一段" >(.*)</a></li>|U", $str, $out);$a = $out[2][0];$b = $out[4][0];echo "a::$a , b::$b";

页面有点大,有没有更高效的方法!!!!!!!

preg_match('#<ul class="style5">(.+?)</ul>#s',$s,$m);preg_match('#<li><a href="/profiles/(\d+)"><img [^ alt="正则截取html中的一段" >]+>(.+?)</a></li>#s',$m[1],$ar);print_r($ar);

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