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参加了去哪儿网的笔试题大意: asp.php.jsp.javascript 语言不限 将其转化为 javascript.jsp.php.asp
意思就是用户输入的字符串(其中包含若干以“.”分隔开来的字符),你写个程序实现以这些“.”为分隔,把原来的一句话倒转过来。
回复讨论(解决方案)
貌似转换成数组,再倒序下就可以了。
问题是如何实现以“.”为分隔呢?两个点之间字符的转化为一个数组单元。大神求解
貌似转换成数组,再倒序下就可以了。
问题是如何实现以“.”为分隔呢?两个点之间字符的转化为一个数组单元。
$s = 'asp.php.jsp.javascript';echo join('.', array_reverse(explode('.', $s)));javascript.jsp.php.asp
$s = 'asp.php.jsp.javascript';echo join('.', array_reverse(explode('.', $s)));javascript.jsp.php.asp
版主大神粗线,看来我的php还得学!谢大神!
<script type="text/javascript">var a='asp.php.jsp.javascript';alert(a.split('.').reverse().join('.'));</script>
如果你不是那种“屡败屡战”型的,建议还是多修炼一段日子再去面试好,不然会一直面对失败打击自己信心的
这是基础吧?
估计是要用非系统自带函数来实现的
这是基础吧?
嗯 当时其实是在纠结自己写函数实现还是什么
估计是要用非系统自带函数来实现的
嗯 当时想到这个了
如果你不是那种“屡败屡战”型的,建议还是多修炼一段日子再去面试好,不然会一直面对失败打击自己信心的
恩恩 谢谢啦!
非系统自带函数来实现,不用array_reverse,就可以这样写吧.
function reverse_str($s){$r=explode('.', $s);$c=count($r);$i=0;foreach($r as $k=>$v){ if($i<$c/2){ $r[$k]=$r[$c-1-$i];//最前面的键值等于最后面的值 $r[$c-1-$i]=$v;//最后面的键值等于最前面的值,以此类推交换键值 $i++; }else{ break; }} return join('.', $r);}//测试$s="1.2.3.4.5.6";echo reverse_str($s);
希望帮到你啊.
非系统自带函数来实现,不用array_reverse,就可以这样写吧.
function reverse_str($s){$r=explode('.', $s);$c=count($r);$i=0;foreach($r as $k=>$v){ if($i<$c/2){ $r[$k]=$r[$c-1-$i];//最前面的键值等于最后面的值 $r[$c-1-$i]=$v;//最后面的键值等于最前面的值,以此类推交换键值 $i++; }else{ break; }} return join('.', $r);}//测试$s="1.2.3.4.5.6";echo reverse_str($s);
希望帮到你啊.
嗯 字符串处理是web开发的很重要的一部分吧。3Q

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