php写每周数据问题代码

php 每周数据

自已写了一段PHP，发现只能读取当今天的数据，前几天的没显示出来，高手看看应怎改。

<?php @header("content-Type: text/html; charset=utf-8");require_once 'inc/site_config.php';require_once 'inc/db_connections.php';require_once 'inc/function.php';mysql_query('set character set "utf8"');?>nbsp;html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><meta><title>无标题文档</title><script></script><!--导航JS--><script></script><!--导航JS--><script></script><!--选项卡--><style><!--@font-face { font-family:"微软雅黑"; src:url("微软雅黑.ttf");} *{margin:0px auto;padding:0px; }body {    color: #666666;    font-size: 12px;}a:link,a:visited,a:hover,a:active{color: #666666;text-decoration: none; font-size:12px;}/*全球经济数据*/#qqjjsj{float:left; overflow:hidden; width:580px; margin-bottom:10px;}#qqjjsj_title{	height:30px;	background:url(http://www.hkjinku.com/statics/2013/element.gif) 0 -109px repeat-x;	margin:0 6px;}#qqjjsj_title li{	float:left;	width:110px;	height:30px;	line-height: 34px;	font-weight:bold;	font-size:14px;	display:inline;	cursor:pointer;	text-align:center;}#qqjjsj_title li.active{	background-image:url(http://www.hkjinku.com/statics/2013/element.gif);	background-position:-2px -60px;	background-repeat:no-repeat;	color:#FFF;}#qqjjsj_title li.unactive{	background-image:url(http://www.hkjinku.com/statics/2013/element.gif);	background-position:0 -109px;	background-repeat:repeat-x;	color:#CCC;}#qqjjsj_content{ float:left; width:570px; border:#381610 5px solid; overflow:hidden;}.tab-hd{ height:30px;}.tab-bd{ height:150px; overflow:hidden;}.tab-bd .scrollFlow{ height:300px; overflow:hidden;}.tab-bd .item{ height:150px; display:block; }.tab-dl dl{ width:100%; height:30px; cursor:pointer;}.tab-dl dl.wi-hd dt,.tab-dl dl.wi-hd dd{ background:url(http://www.hkjinku.com/statics/2013/element.gif) 0 -155px repeat-x; color:#381610;}.tab-dl dl.wi-item:hover dt,.tab-dl dl.wi-item:hover dd{ background:#e5bd78; color:#FFF;}.tab-dl dt,.tab-dl dd{ height:24px; line-height:24px; text-align:center; float:left; display:inline;border:1px solid #CCC;box-shadow:1px 1px 1px #c2c2c2; margin:2px; color:#888888; font-weight:700; font-size:14px; overflow:hidden; }.tab-dl dt{ width:258px;}.tab-dl dd.i1{ width:70px;}.tab-dl dd.i2{ width:70px;}.tab-dl dd.i3{ width:60px;}.tab-dl dd.i4{ width:80px;}.qqjjsj_url{ margin:7px 10px;}--></style><!--全球经济数据-->      <div>              <div>              	<ul>                <?php                $j = 0;                for( $i = 0; $i <7; $i++ ){ //循环输出7天日期                	if( (date('N',strtotime('-'.$i.' day'))) < 6 ){  //排除星期六天                    echo '<li class="'.(( $j == 0 )?"active":"unactive").'" id="qqjjsj'.$j.'" onmouseover="javascript:Show(\''.$j.'\',\'5\',\'qqjjsj\',\'active\',\'unactive\')">'.(date('n月d日',strtotime('-'.$i.' day'))).'';                    $j++;                	}                }				?>                				</ul>              </div>               <div>              	            <?php             $j = 0;            for( $i = 0; $i <7; $i++ ){ //循环输出7天内数据            if( (date('N',strtotime('-'.$i.' day'))) < 6 ){  //排除星期六天                $cur_time = mktime(0, 0, 0, date("m")  , (date("d")-$i), date("Y")); //当天时间戳                $next_time = mktime(0, 0, 0, date("m")  , (date("d")+1-$i), date("Y")); //第二天时间戳                $where = "`AccTime` >= '$cur_time' AND `AccTime` ';                ?>                <div>                    <dl>                    	<dt>事件</dt>                    	<dd>前值</dd>                        <dd>预期值</dd>                        <dd>时间</dd>                        <dd>日期</dd>                    </dl>                </div>                <div>">                	<div>    				<div>" class="item">                <?php $s_arr=array();				$i=0;				$service_rs=mysql_query("select * from info where CateId='8' and $where order by InfoId desc limit 10");				while($service_row=mysql_fetch_assoc($service_rs))				{					$s_arr[$i++]=$service_row;				}								for($i=0;$i<10;$i++)				{			?>                    <dl>                    	<dt><a>" target="_blank">=$s_arr[$i]['Title']?></a></dt>                    	<dd>=$s_arr[$i]['qz']?></dd>                        <dd>=$s_arr[$i]['yqz']?></dd>                        <dd>=$s_arr[$i]['time']?></dd>                        <dd>=$s_arr[$i]['AccTime']?></dd>                    </dl>                  <?php  } ?>                    </div>                    <div>" class="item"></div>                    </div>   <script>scrolltop("#scroll_a<?php echo $j?>","#scroll_b<?php echo $j?>",".scrollBox<?php echo $j?>");</script>                                                    </div>            <?php             	echo '</div>';                $j++;            }            }             ?>              	<div><a>@@##@@</a></div>              </div>                    </div>

回复讨论(解决方案)

第101行 的 for( $i = 0; $i  内嵌第130行的 for($i=0;$i
你觉得合理吗？

原来是那里问题，把130行的改成I1解决了。。

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