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类方法返回值，奇怪的现象

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Jun 23, 2016 pm 02:02 PM

各位大侠，请看如下代码:
我要实现的功能是，利用一个多维数组输出一个树状结构，下面的参数是多维数组。

//递归树状输出格式一

	public function accountTreeType1($arrData){		$this->strLable = $this->strLable.'<ul>';		foreach($arrData as $val){			if(is_array($val['child'])){				$this->strLable = $this->strLable.'<li>'.$val['acc_code'].$val['acc_name'];				$this->accountTreeType1($val['child']);			}else{				$this->strLable = $this->strLable.'<li>'.$val['acc_code'].$val['acc_name'].'</li>';                                 if($val[id]=='最后一个ID')｛                                      return $this->strLable; //在这里没有返回值，不过用echo $this->strLable;是可以打印出来，但是返回值为空。                                 ｝			}		}		$this->strLable = $this->strLable.'</ul>';	}

回复讨论(解决方案)

第 9 行的 $this->accountTreeType1 没有承接第 14 行的返回

第 9 行的 $this->accountTreeType1 没有承接第 14 行的返回

那为什么echo 时，能打印呢

你是如何调用这个方法的？

function return了之后表示该方法已经运行完了，后面的代码都不会执行了。

$str = D('Account')->accountTreeType1($Data);

方法的最后加上
return $this->strLable;

1、class 里strLable定义了没？
2、return了你不接收返回值你是要做什么？
3、echo 当然可以输出，你是不是没搞清楚什么是递归函数？

加了之后，有返回值了。但是不是很理解为什么这样写。

public function accountTreeType1($arrData){
$strLable .= '

'.$val['acc_code'].$val['acc_name'].'

';
}

你都不return 怎么获取值

你都不return 怎么获取值

我刚刚代码有return。只是搞不明白，什么时候return。而且在方法最后面加return，那它递归，每次调用都会return不是吗？

$val[id],id是什么？应该是$id或者"id"吧...所以根本不会返回$this->strLabel

return 是跳出当前方法你刚才其实调用了当前function好几次你递归没搞懂
你最好搞懂
return back continue 和递归

public function accountTreeType1($arrData){
$strLable .= '

$arrData 打印出来看看

public function accountTreeType1($arrData){
$strLable .= '

'.$val['acc_code'].$val['acc_name'].'

'.$val['acc_code'].$val['acc_name'].'

public function accountTreeType1($arrData){
$strLable .= '

这个可以实现。谢谢你们，我有点明白，我错在哪了。

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