1. 2. $id = isset($_POST['id'])? $_POST['id'] : 0;
3. $filename = 'http://saberlily-images.stor.sinaapp.com/' .strval($id). '.jpg';
4. if(file_exists($filename)){
5. echo '';
6. }else{
7. echo '';
8. }
9. ?>
这段代码中 第3行的filename 函数引用的这段代码有什么问题??? 我把路径改成本地却能访问到
但是 "http://saberlily-images.stor.sinaapp.com/load.jpg 这个路径是没问题的,
因为第7行能成功访问到。
问题出在哪儿
求解,谢谢了!
回复讨论(解决方案)
file_exists 就只能检查本地文件,远程用get_headers获取头信息来判断,你这个需求在
var_dump(file_exists('http://saberlily-images.stor.sinaapp.com/load.jpg'));
打印出来为false;
话说file_exists貌似只能用来判断webroot下面的。
$id = isset($_POST['id'])? $_POST['id'] : 0;$filename = 'http://saberlily-images.stor.sinaapp.com/load.jpg';if(getimagesize($filename)){ echo '11<img src="/static/imghwm/default1.png" data-src="'.$filename.'" class="lazy" .$filename.'" style="max-width:90%" height="auto" alt="php代码问题" >';}else{ echo '<img src="/static/imghwm/default1.png" data-src="http://saberlily-images.stor.sinaapp.com/load.jpg" class="lazy" style="max-width:90%" height="auto" alt="php代码问题" >';}
'

外面是单引号,$filename是不能解析的
file_exists只适用于本机或者网络共享文件夹的文件。
file_exists只能判?本地的,判?http的不行。
<?php$filename = '/path/to/foo.txt';if (file_exists($filename)) { echo "The file $filename exists";} else { echo "The file $filename does not exist";}?>
http://cn2.php.net/file_exists
要判??程文件是否存在可以???
function check_remote_file($url){ $result = get_headers($url, 1); if($result[0]=='HTTP/1.1 200 OK'){ return true; }else{ return false; }}$id = isset($_POST['id'])? $_POST['id'] : 0;$filename = 'http://saberlily-images.stor.sinaapp.com/' .strval($id). '.jpg';if(check_remote_file($filename)){ echo '<img src="/static/imghwm/default1.png" data-src=".$filename." class="lazy" style="max-width:90%" height="auto" alt="php代码问题" >';}else{ echo '<img src="/static/imghwm/default1.png" data-src="http://saberlily-images.stor.sinaapp.com/load.jpg" class="lazy" style="max-width:90%" height="auto" alt="php代码问题" >';}
现在我在Dream Weaver能完美运行了,可是上传到SAE服务器上就不显示了。是什么情况
查看下源码,看生成了什么。

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