回复讨论(解决方案)
$base_num 不会被覆盖,
这与 php 的变量作用域有关,函数内的变量只在本函数内有效
也就是说,递归调用的 quick_sort 中的 $base_num 都是独立的
这一点与 js 不同,需要注意。当然 js 中可用 var 声明局部变量
每次执行都是函数体内的局部变量,除非是静态或全局变量才会改变
$base_num 不会被覆盖,
这与 php 的变量作用域有关,函数内的变量只在本函数内有效
也就是说,递归调用的 quick_sort 中的 $base_num 都是独立的
这一点与 js 不同,需要注意。当然 js 中可用 var 声明局部变量
你的意思是,我举个例子,比如:3,1,5,4
第一次穿进去把3拿出来做标尺,1,5,4以此和它做对比,小于它的在left数组,大于它的在right数组,$left=array(1); $right=array(5,4);
当$right再次递归时候,把5拿出来做标尺,4和它对比。那被做标尺的值3和5最后能在最后一行代码
return array_merge($left_array, array($base_num), $right_array);中找到,是这样吧。
这样看的清楚点
print_r(quick_sort(array(6,1,5,8,7,4,2,3,0)));function quick_sort($arr) { //先判断是否需要继续进行 $length = count($arr); if($length <= 1) { return $arr; } //如果没有返回,说明数组内的元素多于 1 个,需要排序 //选择一个标尺 //选择第一个元素 $base_num = $arr[0]; //遍历 除了标尺外所有元素,按照大小关系放入两个数组内 //初始化两个数组 $left_array = array(); //小于标尺的 $right_array = array(); //大于标尺的 for($i=1; $i<$length; $i++) { if($base_num > $arr[$i]) { //放入左边数组 $left_array[] = $arr[$i]; } else { //放入右边数组 $right_array[] = $arr[$i]; } }printf("in[%s] B[%d] L[%s] R[%s]<br>", join(',', $arr), $base_num, join(',', $left_array), join(',', $right_array)); //再分别对 左边 和 右边 得得数组进行相同的排序处理 //递归调用这个函数,并记录结果 $left_array = quick_sort($left_array); $right_array = quick_sort($right_array); //合并左边、标尺、右边 return array_merge($left_array, array($base_num), $right_array);}
in[6,1,5,8,7,4,2,3,0] B[6] L[1,5,4,2,3,0] R[8,7]in[1,5,4,2,3,0] B[1] L[0] R[5,4,2,3]in[5,4,2,3] B[5] L[4,2,3] R[]in[4,2,3] B[4] L[2,3] R[]in[2,3] B[2] L[] R[3]in[8,7] B[8] L[7] R[]Array ( [0] => 0 [1] => 1 [2] => 2 [3] => 3 [4] => 4 [5] => 5 [6] => 6 [7] => 7 [8] => 8 )
这样看的清楚点
print_r(quick_sort(array(6,1,5,8,7,4,2,3,0)));function quick_sort($arr) { //先判断是否需要继续进行 $length = count($arr); if($length <= 1) { return $arr; } //如果没有返回,说明数组内的元素多于 1 个,需要排序 //选择一个标尺 //选择第一个元素 $base_num = $arr[0]; //遍历 除了标尺外所有元素,按照大小关系放入两个数组内 //初始化两个数组 $left_array = array(); //小于标尺的 $right_array = array(); //大于标尺的 for($i=1; $i<$length; $i++) { if($base_num > $arr[$i]) { //放入左边数组 $left_array[] = $arr[$i]; } else { //放入右边数组 $right_array[] = $arr[$i]; } }printf("in[%s] B[%d] L[%s] R[%s]<br>", join(',', $arr), $base_num, join(',', $left_array), join(',', $right_array)); //再分别对 左边 和 右边 得得数组进行相同的排序处理 //递归调用这个函数,并记录结果 $left_array = quick_sort($left_array); $right_array = quick_sort($right_array); //合并左边、标尺、右边 return array_merge($left_array, array($base_num), $right_array);}
in[6,1,5,8,7,4,2,3,0] B[6] L[1,5,4,2,3,0] R[8,7]in[1,5,4,2,3,0] B[1] L[0] R[5,4,2,3]in[5,4,2,3] B[5] L[4,2,3] R[]in[4,2,3] B[4] L[2,3] R[]in[2,3] B[2] L[] R[3]in[8,7] B[8] L[7] R[]Array ( [0] => 0 [1] => 1 [2] => 2 [3] => 3 [4] => 4 [5] => 5 [6] => 6 [7] => 7 [8] => 8 )
这样看的清楚点
print_r(quick_sort(array(6,1,5,8,7,4,2,3,0)));function quick_sort($arr) { //先判断是否需要继续进行 $length = count($arr); if($length <= 1) { return $arr; } //如果没有返回,说明数组内的元素多于 1 个,需要排序 //选择一个标尺 //选择第一个元素 $base_num = $arr[0]; //遍历 除了标尺外所有元素,按照大小关系放入两个数组内 //初始化两个数组 $left_array = array(); //小于标尺的 $right_array = array(); //大于标尺的 for($i=1; $i<$length; $i++) { if($base_num > $arr[$i]) { //放入左边数组 $left_array[] = $arr[$i]; } else { //放入右边数组 $right_array[] = $arr[$i]; } }printf("in[%s] B[%d] L[%s] R[%s]<br>", join(',', $arr), $base_num, join(',', $left_array), join(',', $right_array)); //再分别对 左边 和 右边 得得数组进行相同的排序处理 //递归调用这个函数,并记录结果 $left_array = quick_sort($left_array); $right_array = quick_sort($right_array); //合并左边、标尺、右边 return array_merge($left_array, array($base_num), $right_array);}
in[6,1,5,8,7,4,2,3,0] B[6] L[1,5,4,2,3,0] R[8,7]in[1,5,4,2,3,0] B[1] L[0] R[5,4,2,3]in[5,4,2,3] B[5] L[4,2,3] R[]in[4,2,3] B[4] L[2,3] R[]in[2,3] B[2] L[] R[3]in[8,7] B[8] L[7] R[]Array ( [0] => 0 [1] => 1 [2] => 2 [3] => 3 [4] => 4 [5] => 5 [6] => 6 [7] => 7 [8] => 8 )
这个很直观!谢谢~

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