我的php版本是5.4的,MYsql_query对应到sqlserver中应该是什么呢,是mssql_query吗,为什么会报“mssql_query没有被定义”的错误呢?
回复讨论(解决方案)
没有加载mssql的php扩展
找到php.ini中的
;extension=php_mssql.dll
改成
extension=php_mssql.dll
然后重启apache
没有加载mssql的php扩展
找到php.ini中的
;extension=php_mssql.dll
改成
extension=php_mssql.dll
然后重启apache
这个已经改过了啊,我还加入了php_pdo_sqlsrv_54_ts和php_sqlsrv_54_ts两个扩展库,我连接数据库时是用的pdo连接的sqlserver数据库:$conn = new PDO( "sqlsrv:server=$serverName;Database = $database", $uid, $pwd);
是不是我用PDO连接的数据库,所以用mssql_query就无法使用呢?(新手上来就用sqlserver,很多东西不明白啊)
sqlsrv_query
sqlsrv_query
多谢回复!你说的这个方法确实可以,我的代码如下,可为什么插入失败呢?
是语法有问题还是其他的问题呢,继续请教啊
header("Content-type:text/html;charset=utf-8");
$serverName = "192.168.1.122,1433";
$database = "hr";
$uid = "sa";
$pwd = "awefff;
$connstr = array("Database"=>"$database","Uid"=>"$uid","Pwd"=>"$pwd","CharacterSet" => "UTF-8");
try {
//$conn = new PDO( "sqlsrv:server=$serverName;Database = $database", $uid, $pwd);
$conn = sqlsrv_connect( "$serverName",$connstr);
if( $conn ) {
echo "Connection established.
";
}else{
echo "Connection could not be established.
";
die( print_r( sqlsrv_errors(), true));
}
}
catch( PDOException $e ) {
die( "Error connecting to SQL Server".$e );
}
$bmtx=$_POST['bmtx'];
$gzbm=$_POST['gzbm'];
$bsc=$_POST['bsc'];
$gwmc=$_POST['gwmc'];
$zwzj=$_POST['zwzj'];
$zwcj=$_POST['zwcj'];
$zx=$_POST['zx'];
$ygbh=$_POST['ygbh'];
$ygxm=$_POST['ygxm'];
$sSex=$_POST['sSex'];
echo $bmtx;
echo $gzbm;
$query="insert into 员工档案表 (部门体系,工作部门,办事处,岗位名称,职位职级,职位层级,职系,员工编号,员工姓名,性别) values('$bmtx','$gzbm',$bsc,'$gwmc','$zwzj','$zwcj','$zx','$ygbh','$ygxm','$sSex')";
$result=sqlsrv_query($conn,$query);
if ($result){
echo '插入成功';
}
else{
echo '插入失败';
}
?>
你用中文做表名和字段名?
请把表名和字段名用[]括起,如 [员工档案表] [部门体系] ....
另外,sql server 接受 utf-8 的表名和字段名吗?请核实
你用中文做表名和字段名?
请把表名和字段名用[]括起,如 [员工档案表] [部门体系] ....
另外,sql server 接受 utf-8 的表名和字段名吗?请核实
对,中文做的表名和字段名,不过我之前用query方法对此表做查询都是没有问题的。
用了您的方法还是不管用,另外utf-8的那段代码我去掉了,也没出现什么问题,看来问题也不是这个地方
你用中文做表名和字段名?
请把表名和字段名用[]括起,如 [员工档案表] [部门体系] ....
另外,sql server 接受 utf-8 的表名和字段名吗?请核实
我找到答案了,因为性别那个字段数据库中是规定的2字节,我实际传入的是多个字节,超出了2个字节,所以插入不成功

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