这个是链接mysql的代码,文件名为link.php
$link=mysql_connect(SAE_MYSQL_HOST_M.':'.SAE_MYSQL_PORT,SAE_MYSQL_USER,SAE_MYSQL_PASS);
mysql_select_db(SAE_MYSQL_DB,$link);
mysql_query("set names utf8");
?>
这段是用SQL语句查询的代码,文件名为testmysql.php
include("link.php");
$name = $_GET['name'];
$ticketid = $_GET['ticketid'];
$id=$_GET['id'];
$result = mysql_query("SELECT * FROM 1 WHERE 姓名='$name' AND 准考证号='$ticketid' AND 身份证号='$id'",$link);
while( $row=mysql_fetch_array($result) ){
echo $row['姓名'] . " " . $row['准考证号'];
echo "
";
}
mysql_close($link);
?>
运行后给出的警告:
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in Query/testmysql.php on line 7
回复讨论(解决方案)
用中文 做字段名称好像不是很好,都说第七行错误,自己判断下吧~
mysql_query执行错误,检查下SQL语句是否正确。
打印下result看是不是资源类型
mysql_query执行错误,检查下SQL语句是否正确。
我开始也怀疑是这个问题,但是,我用sql语句在数据库软件上查询是对的呀!
mysql_query执行错误,检查下SQL语句是否正确。
我开始也怀疑是这个问题,但是,我用sql语句在数据库软件上查询是对的呀!
变量用{}包起来

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