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我是php初学者,写了一个到数据库验证用户的简单代码,无论输对的还是错的账号密码都不能通过验证。求高手指点
回复讨论(解决方案)
$res= mysqli_query($conn,$sql);
if($row= mysql_fetch_assoc($res)){
mysql 和 mysqli 是平行的两个扩展,不能混用!
$res= mysqli_query($conn,$sql);
if($row= mysql_fetch_assoc($res)){
mysql 和 mysqli 是平行的两个扩展,不能混用!
请问应当怎么写可以解决问题
$res= mysqli_query($conn,$sql);
if($row= mysql_fetch_assoc($res)){
mysql 和 mysqli 是平行的两个扩展,不能混用!
改成了if ($row=mysqli_fetch_assoc($res))解决了问题,感谢大神
header("Content-type: text/html; charset=utf-8");class cls_Mysqli{ private $db_host="localhost"; private $db_user="root"; private $db_password="root"; private $db_name="test"; protected $sql; public $password; function __construct($id,$password){ $this->password = $password; $this->sql = "select password from admin where id = $id"; } function checkPassword(){ global $link; $link = mysqli_connect($this->db_host, $this->db_user, $this->db_password, $this->db_name) or die("数据库错误: " . mysqli_connect_error()); $res = mysqli_query($link,$this->sql); if ($row_val = mysqli_fetch_row($res)){ if ($this->password == $row_val[0]){ return true; }else{ return false; } } }}$query = new cls_Mysqli(1,'123');print $query->checkPassword();mysqli_close($link);
@xuzuning
if 结构执行了return,这个mysqli资源要怎么释放才合理。

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