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HomeBackend DevelopmentPHP Tutorial如何构造如下json的php数组?

id: 530000, name: '云南', city: [
            {
                id: 530100, name: '昆明市', district: [
                    {id: 530102, name: '五华区'},
                    {id: 530103, name: '盘龙区'},
                    {id: 530111, name: '官渡区'},
                    {id: 2312, name: '西山区'},
                    {id: 2313, name: '东川区'},
                    {id: 2314, name: '呈贡县'},
                    {id: 2315, name: '晋宁县'},
                    {id: 2316, name: '富民县'},
                    {id: 2317, name: '宜良县'},
                    {id: 2318, name: '石林彝族自治县'},
                    {id: 2319, name: '嵩明县'},
                    {id: 2320, name: '禄劝彝族苗族自治县'},
                    {id: 2321, name: '寻甸回族彝族自治县'},
                    {id: 2322, name: '安宁市'}
                ]
            },
            {
                id: 266, name: '曲靖市', district: [
                    {id: 2323, name: '麒麟区'},
                    {id: 2324, name: '马龙县'},
                    {id: 2325, name: '陆良县'},
                    {id: 2326, name: '师宗县'},
                    {id: 2327, name: '罗平县'},
                    {id: 2328, name: '富源县'},
                    {id: 2329, name: '会泽县'},
                    {id: 2330, name: '沾益县'},
                    {id: 2331, name: '宣威市'}
                ]
            }
        ..... ]


最终要返回上面的json数组,

$p = array();$city = array();$district = array();$cityList = query("这个是查询某一个省下的所有市");$districtList   = query("这个是查询某一个市下的所有区");



请问如何拼凑如上数组,最终通过json_encode($p); 来返回一个json数据,谢谢!


回复讨论(解决方案)

谁来帮看看啊

查一下,关联数组

json_encode

先不说这题的难度,这是一个题目,并不是一个技术点
遇到一个题目,首先要先查阅相关资料
http://www.w3school.com.cn/php/php_arrays.asp
http://www.runoob.com/php/php-json.html
学习好基础知识后尝试自己实现
实现过程中遇到困难再来提问,那样即使再小的问题都会有人帮你

$cityList = query("这个是查询某一个省下的所有市");
for($cityList) 对每个查到的市 
   $districtList   = query("这个是查询某一个市下的所有区");
   附加 $districtList 到 $cityList 对应项

这个要看你的表结构
然后写2层循环     首先   省份的地方   pid=0   其余的  地下的市级pid = 省份的id

比如   山东省  id = 1 pid =0  济南市 id = 2  pid = 1  青岛市  id = 3 pid= 1

$cityList = query("这个是查询某一个省下的所有市");
for($cityList) 对每个查到的市 
   $districtList   = query("这个是查询某一个市下的所有区");
   附加 $districtList 到 $cityList 对应项




-------------------------------------
以前是搞.net转过来的,我现在就是不知道,如何“附加 $districtList 到 $cityList 对应项”,.net的话,直接用list.add(otherList)add方法就可以了,php没搞懂是怎么添加进去的

先不说这题的难度,这是一个题目,并不是一个技术点
遇到一个题目,首先要先查阅相关资料
http://www.w3school.com.cn/php/php_arrays.asp
http://www.runoob.com/php/php-json.html
学习好基础知识后尝试自己实现
实现过程中遇到困难再来提问,那样即使再小的问题都会有人帮你




===========================================
这个就是个技术点,我就是想问一下,如何把一个子数组添加到父数组里面,这个知识点,之前网上搜索没找到

$parent = array('aaa' =>1);
$child = array('ccc' => 1);
$parent['bbb'] = $child;   //这样就可以了
print_r($parent);

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