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HomeBackend DevelopmentPHP Tutorial网站–微信–后端报错机制【原创】

基于项目开发的需求,总结出网站开发常见的异常提醒包括异常错误的提示页面以及返回登录页面之后的回跳问题,虽然两种都有简便的方法进行处理,但是都存在各自明显的缺陷和调用上的麻烦之处。所以经过开发论证,本人自己搭建了一个网站类项目的后端报错机制。目前虽然功能单一,但我以为这是一个好的方向。

以下代码是基于Symfony框架写的源码

调用端

报错的点引用方法,传递必要参数,进入报错处理流程

/**     * 异常处理机制     *     * @param bool|false $default     是否跳转默认的路由  true真  flase 假     * @param string $message         错误信息  ''自动跳到登录页面  不为空则跳到提示页面     * @param array $data             记录访问此路由的post的参数用于回跳--需要注意的是post提示中不得有文件类型和数组类型否则回调必然会报参数丢失(传参_POST)     * @param string $url             默认为空 当defaulet设置为true时此参数生效,用户替换已设置的默认路由     * @param int type                默认为1  1为返回页面  其余则代表返回路由用户ajax请求     * @return \Symfony\Component\HttpFoundation\RedirectResponse       */    public function exception_handling($default = false, $message = '', $data = array(), $url = '', $type = 1)    {        if ($message != '') {            //这里的强制处理,是避免程序因为某个参数的丢失陷入死循环            $default = true;          }        //封装参数        $info = array(            'data' => $data,        );        if ($default == true) {            //跳转到默认的路由            if ($url == '') {                $info['url'] = $this->get('request')->getSchemeAndHttpHost() . $this->generateUrl('wx_index');//需要重新设置替换            } else {                $info['url'] = $url;            }            $info['data'] = array();        } else {            $http_host = $_SERVER['HTTP_HOST'];            $php_self = $_SERVER['PHP_SELF'];            $query = $_SERVER['QUERY_STRING'];            $info['url'] = 'http://' . $http_host . $php_self;            if ($query != '') {                $info['url'] .= '?' . $query;            }        }        //对原有的值进行封装        if (!empty($data)) {            $i = 0;            foreach ($data as $index => $value) {                $info['info'][$i]['key'] = $index;                $info['info'][$i]['value'] = $value;                $i++;            }        }        //将数据序列化打包        unset($info['data']);        $info = urlencode(base64_encode(@serialize($info)));        if ($message == '') {            //跳转到登录页面            if ($type == 1) {                return $this->redirect($this->generateUrl('wx_auth_login', array('info' => $info)));//需要重新设置替换            } else {                return $this->get('request')->getSchemeAndHttpHost() . $this->generateUrl('wx_auth_login', array('info' => $info));//需要重新设置替换            }        } else {            //跳转到错误页面            if ($type == 1) {                return $this->redirect($this->generateUrl('api_wx_other_err', array('message' => $message, 'info' => $info))); //需要重新设置替换            } else {                return $this->get('request')->getSchemeAndHttpHost() . $this->generateUrl('api_wx_other_err', array('message' => $message, 'info' => $info)); //需要重新设置替换            }        }    }

接收端处理方式

1:对于路由参数info的处理和跳转方法【此处方法主要用于登录需要回跳的有关页面】

/**     * @param $info   报错机制传递来封装参数info     * @return string   返回url     */    public function login_ok_url($info)    {        if (!is_array(@unserialize(base64_decode(urldecode($info))))) {            $url = $this->get('request')->getSchemeAndHttpHost() . $this->generateUrl('wx_index');//需要重新设置替换  默认页        } else {             $url = $this->get('request')->getSchemeAndHttpHost() . $this->generateUrl('api_wx_other_postJump', array('info' => $info)); //需要重新设置替换  报错回跳处理器        }        return $url;    }

2:错误提示页面跳转逻辑

/**     * 错误提示页面     *     * @param $message     * @param $info     * @return \Symfony\Component\HttpFoundation\Response     */    public function errAction($message , $info){        //得到传来的post参数用于页面再次提交        $url = $this->get('request')->getSchemeAndHttpHost() . $this->generateUrl('api_wx_other_postJump', array('info' => $info));        //回跳按钮上面的字        $info = @unserialize(base64_decode($info));        if(!is_array($info) || $info['url'] == $this->get('request')->getSchemeAndHttpHost() . $this->generateUrl('wx_index')) { //需重新配置            $url = $this->get('request')->getSchemeAndHttpHost() . $this->generateUrl('wx_index');            $text = '返回首页';        }else{            $text = '返回上一页';        }        return $this->render('@Api/Default/wx_message.html.twig',array('data' => array('message' => $message, 'url' => $url ,'text' => $text)));    }

报错回调处理控制器(核心方法)–用于拆解封装好的参数进行相应的请求跳转

/**     * 内部post请求     *     * @param $info     * @return \Symfony\Component\HttpFoundation\RedirectResponse|Request     */    public function postJumpAction($info){        //将数组转换        $info = @unserialize(base64_decode(urldecode($info)));        if(!is_array($info)) {            $url = $this->get('request')->getSchemeAndHttpHost() . $this->generateUrl('wx_index'); //重新配置        }else{            $url = $info['url'];        }                if(empty($info['info'])){            return $this->redirect($url);        }else{            return $this->render('@Api/Default/postJump.html.twig', array('data' => $info));//重新配置        }    }

两个重要的模板

1:postJump.html.twig模板–用户再次向目标路由发送post请求

<html><head>    <meta charset="UTF-8">    <title>正在跳转...</title></head><body><div id = 'hide'><form id="myForm" action= '{{ data.url }}' method="post" >            {% for item  in data.info %}                <input type="hidden" name= "{{ item.key }}" value="{{ item.value }}" >            {% endfor %}            <input type="submit" id="submit" value="正在跳转...">        </form>    </div><script src="{{ asset('js/jquery-1.11.3.min.js') }}"></script><script>    $(function () {        $('#submit').trigger("click");    })</script></body></html>

2:提示模板wx_message.html.twig,根据控制器和自己项目的特点进行嵌套就可以了返回值

data.url          回跳的URl                    data.message      错误信息                    data.text         回跳按钮上的字

如果有更好的建议请在帖子下面留言,会积极听取的

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