大概的要求就是点击左侧的问题,右侧出现该问题的所有的回答.问题我已经从数据库中调用.
我的想法
1.是先从数据库总查询出该问题的答案,然后写下来,然后通过jquery显示出来 (或者写入)
2.还是通过jjquery取得该问题的id,传真给thinkphp,查询数据库后,输出?()
3.是不是要用到ajax?
应该选择哪个,大概如何实现
因为我只看了w3c的jquery教程,所有有点不知道从何下手,新手,描述的有点不清楚.
回复讨论(解决方案)
你说的第2点就要用到ajax
至于1还是2好,取决于问题的数量
只有几十个干脆直接查出答案,通过js点击改变右边div内容
如果问题很多,还带翻页,就要ajax查了
jquery:
$.get(url?id=123, function(data){alert(data)})
thinkphp:
$this->ajaxReturn($data);
前台JQ修改CSS
后台一次查询一页的数量+分页AJAX查询
你说的第2点就要用到ajax
至于1还是2好,取决于问题的数量
只有几十个干脆直接查出答案,通过js点击改变右边div内容
如果问题很多,还带翻页,就要ajax查了
jquery:
$.get(url?id=123, function(data){alert(data)})
thinkphp:
$this->ajaxReturn($data);
感谢,按照你的,我已经做出来点击左侧问题,出现右侧,答案,
还有个点赞功能想要做.不知道为什么按照现在的方法,不能实现呢
1.jquery改变html后添加的内容,是不是不能再接受点击事件了
2.我的想法是 点赞 跟 鄙视 两个点击后指向2个不用的function 查找后修改对应的数据库字段.这样的思路对么?
$data = $data."<br><p >".$v['id'].":".$v['text']."<br><a class='zhan' href='#'><i></i><span id=".$v['id']." class='num'>0</span></a><a class='zhan'' href='#'><i class='i2'></i><span>0</span></a></p>"; } }else{ $data ="没有满足条件的答案"; } $this->ajaxReturn($data); }
//点击出现对应答案 $(document).ready(function(){ $(".qsn").click(function(){ // alert( $(this).attr('id')); $.get("{$smarty.const.__CONTROLLER__}/ask/id/"+ $(this).attr('id'), function(data){ // alert("Data: " + data ); $('#ans').html(data); // document.write(data); }); }) })
$(document).ready只能给页面刚开始的按钮绑定事件
你给点赞按钮加一个class:js_up,然后加一个id="123"
然后jquery里写:$('.js_up').live('click', function(){ajax提交点赞,id就是按钮的id属性})
错了,是$(".qsn").click
只能初始时绑定事件,你后面ajax补进来的按钮绑不上,要用live

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