如何进行checkbox的选中判断
- PHP code
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --><?php while($row=mysql_fetch_array($result)){ ?> <tr> <td width="10" scope="col" bgcolor="#E0EEE0"><input type="checkbox" name="shanchu[]"></td> <td>.....</td> <td>.....</td> <td>还有很多数据,省略</td> </tr> <?php include('conn.php'); $delete=$_POST['shanchu']; foreach($delete as $k=>$v){ $sql="delete from record"; //这块应该怎么写? 能不能只判断checkbox选中的情况而 不看其他的数据? $result=mysql_query($sql,$con); } if($result!=""){ echo "数据删除成功"; echo "<br>"; echo "正在返回删除页面,跳转中..."; echo "<meta http-equiv="refresh" content="2;url=shanchu.php">"; } else { echo "数据输入错误"; echo "<br>"; echo mysql_error(); } ?>
第一改动:一点改进
sql语句变成这样$sql="delete from record where no='$shanchu[$k]'";
Parse error: syntax error, unexpected $end
in C:\AppServ\www\deleterecord.php on line 29
第二次改动
把下面的删除的php单独到一个文件中,进行处理
无错误提示 提示数据删除成功 但实际上无效果 求解 这是什么原因?
------解决方案--------------------
删除记录需要有唯一的标识,不然就可能误删
一般表中都有主键 id,这就是唯一的标识
于是表单里
.../>...
这样就和表中的记录对应起来了
删除时
$sql = 'delete from record where id in (' . join(',', $_POST['shanchu']) . ')';
------解决方案--------------------
如何进行checkbox的选中判断
print_r($_POST);
------解决方案--------------------
echo $sql;
------解决方案--------------------

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