ajax.call是什么意思???
{$link.link_id} |
这段代码调用了listTable.toggle函数
listTable.toggle = function(obj, act, id)
{
var val = (obj.src.match(/yes.gif/i)) ? 0 : 1;
var res = Ajax.call(this.url, "act="+act+"&val=" + val + "&id=" +id, null, "POST", "JSON", false);
if (res.message)
{
alert(res.message);
}
if (res.error == 0)
{
obj.src = (res.content > 0) ? 'images/yes.gif' : 'images/no.gif';
}
}
这里的/yes.gif/i的i是干嘛用的,还有ajax.call是什么意思???
------解决方案--------------------
ecshop?
var res = Ajax.call(this.url, "act="+act+"&val=" + val + "&id=" +id, null, "POST", "JSON", false);
这是封过的一个方法,根据参数可知
this.url为请求url
中间act=&...这都是传的参数
POST方式,返回JSON类型
null和false可能是设置回调函数
(obj.src.match(/yes.gif/i)) ? 0 : 1;
这是三目运算符,在对象src属性里查yes.gif
/i是不区分大小写,属正则表达式内容
作用是,若src内有yes.gif返回0否则1
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