求助。在学习的过程中Sqlhelper类中的连接总是不正确
学习写一个登陆小程序。三个文件SqlHelper.class.php,loginProcess.php,AdminService.class.php
我用的是zend开发工具。运行代码的时候总是报:Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in C:\wamp\www\empManage\SqlHelper.class.php on line 20
我猜想是类实例化之后构造函数的问题。
但是总是无法解决。希望有人帮我看下。非常感谢
SqlHelper.class.php
<br /> <?php<br /> class SqlHelper{<br /> //声明类成员<br /> public $conn;<br /> public $dbname="emp";<br /> public $username="root";<br /> public $password="";<br /> public $host="localhost";<br /> //构造函数<br /> public function _construct(){<br /> $this->conn=mysql_connect($this->host,$this->username,$this->password);<br /> if (!$this->conn) {<br /> die("连接失败".mysql_error());<br /> }<br /> mysql_select_db($this->dbname,$this->conn);<br /> }<br /> <br /> // 执行dql语句<br /> public function excute_dql($sql){<br /> $res=mysql_query($sql,$this->conn) or die(mysql_error());<br /> return $res;<br /> }<br /> <br /> //执行dml语句<br /> public function excute_dml($sql){<br /> $b=mysql_query($sql,$this->conn);<br /> if (!$b){<br /> return 0;<br /> }else{<br /> if(mysql_affected_rows($this->conn)>0){<br /> return 1;//表示执行OK<br /> } else{<br /> return 2;//表示执行没有行受到影响<br /> }<br /> <br /> }<br /> <br /> <br /> }<br /> //关闭数据库连接<br /> public function close_connect(){<br /> if (!empty($this->conn)){ <br /> mysql_close($this->conn);<br /> }<br /> }<br /> }<br /> ?><br />
AdminService.class.php:
<br /> <?php<br /> require_once 'SqlHelper.class.php';<br /> class AdminService{<br /> public function checkAdmin($id,$password){<br /> $sql="select * from admin where id=$id";<br /> //创建一个SqlHelper对象<br /> $sqlHelper=new SqlHelper();<br /> $res=$sqlHelper->excute_dql($sql);//我把这个结果给你,你怎么处理是你的事情<br /> if ($row=mysql_fetch_assoc($res)){<br /> if ($password==$row['password']){<br /> return $row['name'];<br /> }<br /> }<br /> //关闭资源<br /> mysql_free_result($res);<br /> $sqlHelper->close_connect();<br /> //关闭连接<br /> return "";<br /> }<br /> }<br /> ?><br /> <br />
loginProcess.php
require_once 'AdminService.class.php';
$id=$_POST['id'];
$password=$_POST['password'];
$adminService=new AdminService();
if($name=$adminService->checkAdmin($id,$password)){
header("Location:empMain.php?name=$name");
exit();
} else{
header("Location:login.php?errno=1");
exit();
}
------解决方案--------------------

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