怎么通过数据库来实现对应数据的输出(描述的可能有点有关问题，内详) -PHP Tutorial-php.cn

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怎么通过数据库来实现对应数据的输出(描述的可能有点有关问题，内详)

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Jun 13, 2016 pm 12:56 PM

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如何通过数据库来实现对应数据的输出(描述的可能有点问题，内详)？
现在的代码，已在最后附上。我想添加办公室名称的话，直接用insert into进officename那个表就可以了
但是，这里officename与officecode是通过JS写死了。如果这样添加的话，两者的对应就有问题了，新添加的数据，是没有对应的officecode的，这就需要手动在js代码里添加，感觉这样很不合理。

所以我想的是不通过js,而是直接从数据库读取，officename表中共建立两个字段name与code
直接通过读取数据库，将两者来进行对应，这样是否可行。需要怎样操作，最好有实例，谢谢

<br />
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"><br />
<br />
<head><br />
<script language="javaScript"><br />
 function setofficecode()<br />
{<br />
    //获取officename/officecode的值<br />
  var officename = document.getElementById("officename").value;<br />
  var o = document.getElementById("officecode");<br />
   //条件判断<br />
   if(officename == "XX办公室"){<br />
	o.value="101";<br />
   }<br />
   else if(officename == "YY办公室"){<br />
	o.value="201";<br />
   }<br />
   else if(officename == "ZZ办公室"){<br />
	o.value="301";<br />
   }<br />
<br />
 }<br />
</script><br />
</head><br />
<br />
<br />
<form action="study3.php" method="post"><br />
<div align="center"><br />
<table><br />
  <tr><br />
  <td>办公室名称</td><br />
  <td><br />
  <select name="officename" id="officename" onchange="setofficecode()" style="width:150px;"><br />
<?php<br />
include('conn.php');<br />
 $sql="select * from officename";<br />
 $query=mysql_query($sql);<br />
 while($result=mysql_fetch_array($query)){<br />
  ?><br />
 <option value="<?=$result[officename]?>"><?=$result[officename]?></option><br />
 <?php<br />
 }<br />
 ?><br />
  </select><br />
  </td><br />
  </tr><br />
  <tr><br />
  <td>办公室号码</td><br />
  <td><input type="text" name="officecode" id="officecode" style="width:150px;" value="101"  /></td><br />
  </tr><br />
</table><br />
<br />
<input type="submit" value="提交" /><br />
</div><br />
<br />
<br />
</form><br />

------解决方案--------------------
改好了

<meta><br>
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