execute_dql_fenye($sql1,$sq12,$fenyePage); $sqlHelper->close_co"/> execute_dql_fenye($sql1,$sq12,$fenyePage); $sqlHelper->close_co">

Home >Backend Development >PHP Tutorial > 上一行就是$sql2的赋值,但是在运行程序的过程中,却报错,提示$sql2未声明,咋回事

上一行就是$sql2的赋值,但是在运行程序的过程中,却报错,提示$sql2未声明,咋回事

WBOY
WBOYOriginal
2016-06-13 12:51:02876browse

上一行就是$sql2的赋值,但是在运行程序的过程中,却报错,提示$sql2未声明,怎么回事?
$sql2="select count(id) from emp";
$sqlHelper->execute_dql_fenye($sql1,$sq12,$fenyePage);
$sqlHelper->close_connect();
------解决方案--------------------
你第二行是sq12,sq十二啊
------解决方案--------------------
嗯,哈哈,一个是sql二,一个是sq十二

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