PHP 在地址栏里乱输入,导致CSS样式失效.如何让跳转到指定页面
例:www.test.com/test.php 如果我在地址栏里乱输入,www.test.com/test.php /sdfsdf/klklj 结果导致 test.php CSS样式失效.请高手指点,当输入这些不存在页,如何跳转到一个错误处理页,如www.test.com/error.php
------解决方案--------------------
伪静态,不符合规范的url可跳到自定义404页面
不知你说的csssu样式失效是何意啊
难道页面其他数据正常显示吗
------解决方案--------------------
采用相对根目录的路径或者绝对路径引用css
------解决方案--------------------
+1

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