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A brief discussion on Javascript nested functions and closures_javascript skills

WBOY
WBOYOriginal
2016-05-16 18:16:43929browse
【Nested Functions】
JavaScript allows embedded functions, allows functions to be used as data, and under the function lexical scope, it can produce surprising differences from traditional object-oriented languages.
First of all, JavaScript functions are scoped lexically, rather than dynamically. Therefore, functions run in the scope in which they are defined, not in the scope in which they are executed. , so it is easy to understand when the nested function and its surrounding function are defined in the same lexical scope. For example, the following very bland code:
Copy the code The code is as follows:

var x = 'global';
function f () {
var x = 'local';
function g() {
alert(x);
}
g();
}
f(); // 'local'

When f() is called, the scope chain can be understood as consisting of two parts, including the call of f object, followed by the global object. At this time, when searching for the value of x, it will first be searched from the calling object of f. If it is not found, x will be searched for in the subsequent global object. In the same way, since g is a nested function of f, when g is called, the scope chain should consist of three parts, the calling object of g, the calling object of f, and the global object. Function g is to output the value of x, so it first searches for the value of x in the calling object of g. There is no definition in g. Then it searches for the definition of x in the peripheral f calling object, so it finds x='local', then It will output x instead of continuing to search for the global object. If the value of x is not defined in f, then it will continue to search for the global object behind the scope chain, and the result will be global. If it is not defined in the global object, then it is naturally undefined.
Okay, we have a preliminary understanding of the scope chain. At the same time, we know that closures have two common uses. One is that it can be used to access local variables, and the other is that it can be used peripherally. The variable values ​​in the field are stored in memory and are not destroyed after the function call is completed.
Next let’s look at a mundane example, which may help understand why closures can save external variable values ​​​​in memory.
Copy code The code is as follows:

function makeFunc (x) {
return function ( ) {return x }
}
var a = [makeFunc(0), makeFunc(1), makeFunc(2)];
alert(a[0]());
alert( a[1]());
alert(a[2]());

The execution results are 0,1,2; there is nothing special, this is also strict Normal behavior of lexical scope. After each makeFunc call is completed, its calling object will be removed from the scope chain, and there will no longer be any reference to it, and it will eventually be completed through garbage collection. To be more detailed, we can understand it this way.
Every time makeFunc is called, a calling object will be created for it and placed in the scope chain. For the function makeFunc, the calling object contains an attribute When the function is executed, a calling object will be created and placed in the scope chain. The anonymous function returns the value of x. (Note: There is no definition of x in the calling object of the anonymous function, so it will refer to its surrounding function. The calling object of makeFunc (accesses Since its calling object contains x, x is also destroyed when it is destroyed. Will not be saved.
The above is the detailed execution process of the function. Please understand it carefully and look at the changed code below:
Copy code Code As follows:

var x = 0;
function makeFunc () {
return function () {return x }
}
var a = [makeFunc(), makeFunc(), makeFunc()];
alert(a[0]());
alert(a[1]());
alert(a[2]());

Now x is a global variable, and the execution results are 0, 1, 2; but this result is somewhat different from the above. Next, we will understand the reason for this result from the perspective of the scope chain.
Similarly, each time makeFunc is called, it will create a calling object into the scope chain. Since it returns a reference to the internal nested function, the internal nested function starts to execute and creates a calling object for the nested function. scope chain. Then return the value of x. Note that it is different here. There is no x in the calling object of the nested function, and there is no x in the calling object of its surrounding makeFunc. We can only search down to the global object. In the global object The definition of x is found, so it is executed normally, the value of x is returned, x is incremented by 1, then the nested function is completed, the calling object is removed, then makeFunc is completed, and the calling object is also removed, but because there is no x in their calling objects , the destruction of their calling objects will not affect x at all. As a result, the change in the value of global variable x is saved.
Note that the above-mentioned access to the outer calling object is only to help understanding and is not strict. JavaScript will not directly access the calling object in any way. However, the properties it defines are part of the scope chain in the calling object. Still "alive". In addition, if a peripheral function contains two or more nested functions that all have references to the global object, then these nested functions all share the same global calling object, and changes to the global object by one of them are visible to the others. of.
Okay, in JavaScript, a function is a complex composed of the code to be executed and the scope in which these codes are executed. Broadly speaking, we can call this complex of code and scope a closure.
 【Closure】
We occasionally need to write a function that needs to be called to remember the value of a variable. Therefore, if we understand scope, we will know that local variables are difficult to achieve because the calling object of the function cannot be maintained after the call. Global variables can do this, as in the above example, but this can easily cause global variable pollution. Since the calling object cannot be maintained, shouldn't we just save the value in the calling object? ! So, here is one way to do it: save it with the properties of the function object itself.
Copy code The code is as follows:

uniqueID = function () {
if (! arguments.callee.id) arguments.callee.id = 0;
return arguments.callee.id ;
}
alert(uniqueID()); //0
alert(uniqueID()) ; //1

As above, because the function itself is an object, it is feasible for us to save it with one of its own attributes, but there is a problem with this, that is, anyone can save it at any time You can force access to the value we originally saved through unqueID.id and make modifications. This is what we don't want to see.
So, usually, we use closures to achieve this. As follows:
Copy code The code is as follows:

_uniqueID = (function(){
var id = 0;
return function () {return id }
})();
alert(_uniqueID()); //0
alert(_uniqueID()); //1

Similarly, we also use the use domain to explain the results. Notice that _uniqueID itself is an anonymous function, and there is an anonymous nested function inside it. What we call directly is _uniqueID(), that is to say, what we directly call is actually the nested function inside _uniqueID, and it The calling object itself does not define an id, so it references the id in the surrounding calling object and returns it. The id is incremented by 1. After execution is completed, the inner nested function calling object moves out of the scope chain. The peripheral ID was not destroyed, so it was saved like this.
Some people may be confused, isn’t it said that the calling object has removed the scope chain after the function is executed? The peripheral anonymous function (function(){})(); has also been called, so the calling object should not have That's right.
Yes, the calling object ends its reference after the current function is executed, but don’t misunderstand the above _uniqueID() call. It is not a directly called peripheral function, but a nested function called. The scope chain of the set of functions includes the scope chain of the surrounding function. Therefore, when its calling object removes the scope chain, it can access and change the properties of other objects in this scope chain.
Closure itself is a difficult to understand but very useful thing. I hope it can be of some help to those in need. In addition, due to limited qualifications, my understanding may be wrong. If I find it, please correct me.
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