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ajax技术 始终出去发送状态,该如何解决
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- 2016-06-13 12:29:37823browse
ajax技术 始终出去发送状态
ajax.js代码：
var xmlHttp;
function S_xmlhttprequest(){
if(window.ActiveXObject){
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
}
else if(widow.XMLHttpRequest){
xmlHttp=new XMLHttpRequest();
}
}
function funphp100(url){
S_xmlhttprequest();
xmlHttp.open("GET","for.php?id="+url,true);
xmlHttp.onreadystatechange=byphp;
xmlHttp.send(null);
}
function byphp(){
if(xmlHttp.readyState==1){
document.getElementById('php100').innerHTML="loading....";
}
if(xmlHttp.readyState==4){
var byphp100 = xmlHttp.responseText;
document.getElementById('php100').innerHTML=byphp100;
}
}
for.php代码
if($id=$_GET[id]){
for($i=1;$i
echo $i;
sleep(2);
}
exit();
}
?>
index.php代码：
<script></script>
o
t
x
if($id=$_GET[id]){<br />
for($i=1;$i<=5;$i++){<br />
<br />
echo $i;<br />
//sleep(2);<br />
}<br />
exit();<br />
}<html><br />
<head><br />
<title> </title> <br />
<script type="text/javascript" src='jquery-1.4.2.min.js'></script><br />
<br />
</head><br />
<script type="text/javascript"><br />
var xmlHttp;<br />
function S_xmlhttprequest(){<br />
if(window.ActiveXObject){<br />
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");<br />
}<br />
else if(window.XMLHttpRequest){<br />
xmlHttp=new XMLHttpRequest();<br />
}<br />
}<br />
function funphp100(url){<br />
S_xmlhttprequest();<br />
xmlHttp.open("GET","test.php?id="+url,true);<br />
xmlHttp.onreadystatechange=byphp;<br />
xmlHttp.send(null);<br />
}<br />
function byphp(){<br />
if(xmlHttp.readyState==1){<br />
document.getElementById('php100').innerHTML="loading....";<br />
}<br />
if(xmlHttp.readyState==4){<br />
<br />
var byphp100 = xmlHttp.responseText;<br />
document.getElementById('php100').innerHTML=byphp100;<br />
<br />
}<br />
<br />
}<br />
<br />
</script><br />
<body><br />
<a href= "#" onclick="funphp100('o')">o</a><br />
<a href= "#" onclick="funphp100('t')">t</a><br />
<a href= "#" onclick="funphp100('x')">x</a><br />
<br><br />
<div id="php100"></div><br />
</body><br />
</html>
else if(widow.XMLHttpRequest){xmlHttp=new XMLHttpRequest();
}
window