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javascript closure question_javascript skills

WBOY
WBOYOriginal
2016-05-16 18:12:561022browse
Copy code The code is as follows:

var test=(function() { var arr2=[1,2 ,3,3]; return function(){ return arr2; }; })()
Array.prototype.f1= function () { return []; }
Array.prototype.f2= function () { this.length=0; return this; }  

Then call it in two ways:
One: var arr= test();
console. log(arr.length); the result is 4
arr.f1();
arr= test();
console.log(arr.length); the result is 4
This is easy to understand;

Two: var arr= test();
console.log(arr.length); the result is 4
arr.f2();
arr= test();
console.log(arr.length); the result is 0
I don’t know why this is happening. Could it be that arr.f2() can modify arr2 in the closure in the test function?
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