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生手上路（关于mysql_fetch_array）
- WBOYOriginal
- 2016-06-13 12:12:16849browse
新手上路（关于mysql_fetch_array）
include 'con_db.php';
$sqlsl="SELECT * FROM `phptestdb`.`inputtest`";
$dbdate=mysql_query($sqlsl)or die(mysql_error());
while($list=mysql_fetch_array($dbdate)){
?>
| =$list[content]?> | |
| 用户：=$list[user]?> | 时间：=$list[date]?> |
___________________________________________________________________________________________________________________________________________________
测试提示：
undefined constant content - assumed 'content'
Use of undefined constant user - assumed 'user'
Use of undefined constant date - assumed 'date'
才刚上路，求知道的人指点，万分感谢！
------解决思路----------------------
=$list['content']?>
加上引号，其他类同
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