Home > Article > Backend Development > 很菜的前后台交互程序，用jq,ajax，json格式，解决方案
很菜的前后台交互程序，用jq,ajax，json格式，解决方案
- WBOYOriginal
- 2016-06-13 12:11:46763browse
很菜的前后台交互程序，用jq,ajax，json格式，
前台输意一个数字，后台处理，比如加2，再返回前台，求教。请别嘲笑。
------解决思路----------------------
html代码部分：
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><br /><html xmlns="http://www.w3.org/1999/xhtml"><br /><head><br /><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><br /><title>无标题文档</title><br /><script src="http://cloud.xing-xing.com/jquery.js"></script><br /><script type="text/javascript" language="javascript"><br />$(function(){<br /> $.get('handle.php',{num:1},function(data){<br /> $("div").html(data);//在div里面输出3<br /> }) <br />})<br /></script><br /></head><br /><body><br /><div></div><br /></body><br /></html>handle.php代码部分：
<?php<br />echo $_GET['num']+2;<br />?>
Statement：
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Previous article：yii 2.0 GridView-自定义按钮跟链接Next article：[date],该如何处理