我想在php中根据用户输入的参数在sql语句中建立表格
比如我现在用$_GET[‘tablename’]来了用户的输入值,我想在php文件中用sql语句create一个名字叫$_GET[‘tablename’]的表格,请问
create table [tablename]这里的tablename如何表示呢这句sql语句才是正确的
我用 create table {. $_GET[‘tablename’]. }不能实现啊?
------解决方案--------------------
$sql = <<<SQL<br />create table {$_GET['tablename']}<br />...<br />SQL;
------解决方案--------------------
= heredoc 句法结构:
<br /><?php <br />$content = <<<FDIPZONE <br /><html> <br /><head> <br /><title>test</title> <br /></head> <br /><body> <br /><p><img src="/static/imghwm/default1.png" data-src="http://www.csdn.net/css/logo.png" class="lazy" alt="小弟我想在php中根据用户输入的参数在sql语句中建立表格" ></p> <br /><p><a href='http://blog.csdn.net/fdipzone'>blog</a></p> <br /></body> <br /></html> <br />FDIPZONE; <br /> <br />echo $content; <br />?> <br />
參考:http://blog.csdn.net/fdipzone/article/details/24937669
------解决方案--------------------
這樣就可以了。
<br />$sql =<<<SQL<br />CREATE TABLE `{$_GET['tablename']}` (<br /> `id` int(10) unsigned NOT NULL auto_increment,<br /> `name` varchar(100) NOT NULL,<br /> `age` tinyint(4) unsigned NOT NULL,<br /> `addtime` datetime NOT NULL,<br /> PRIMARY KEY (`id`)<br />)<br />SQL;<br /><br />mysql_query($sql) or die(mysql_error());<br />

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