求PHP算法 求大神帮助
我有一个需求 写一个 足球联赛的 算法。
需求是这样的 很简单 有六只球队
A1 A2 A3 A4 A5 A6
然后 如果一轮一场比赛的话
第一论
A1VSA2 A3VSA4 A5VSA6
第二轮
A1VSA4 A2VSA5 A3VSA6
第三轮
....
每个球队都会跟 其他五个球队比赛10次 其中 主场5次 客场5次 (他在前和 在后)
这么个算法 愁死我了
最后就要 按照 一轮一场 如 让用户选择 第二轮 就会 列出 第二轮 谁和谁的比分来!
------解决方案--------------------
$a = array('A1', 'A2', 'A3', 'A4', 'A5', 'A6');<br /><br />berger_method($a);<br /><br />function berger_method($ar) {<br /> if(count($ar) %2) $ar[] = ' ';<br /> $t = array_merge(range(1, count($ar)-1), range(1, count($ar)-1));<br /><br /> $len = count($ar);<br /> $m = range(1, $len);<br /> $lun = 0;<br /> $last = 0;<br /> $k = $len <= 4 ? 1 : ($len - 4) / 2 + 1;<br /> while($lun++ < $len-1) {<br /> $s = array_values($m);<br /> echo "== $lun ==\n";<br /> for($i=0; $i<$len/2; $i++) printf("%s -- %s\n", $ar[$s[$i]-1], $ar[$s[$len-1-$i]-1]);<br /> echo "\n";<br /><br /> list($m[0], $m[$len-1]) = array($m[$len-1], $m[0]);<br /> for($i=0; $i<$k; $i++) {<br /> if($m[++$last % $len] == $len) $last++;<br /> }<br /> $n = $last %= $len;<br /> for($i=1; $i<$len; $i++) {<br /> if(($m[$n]) == $len) $n = ($n + 1) % $len;<br /> $m[$n] = $i;<br /> $n = ($n + 1) % $len;<br /> }<br /> }<br />}<br />
== 1 ==<br />A1 -- A6<br />A2 -- A5<br />A3 -- A4<br /><br />== 2 ==<br />A6 -- A4<br />A5 -- A3<br />A1 -- A2<br /><br />== 3 ==<br />A2 -- A6<br />A3 -- A1<br />A4 -- A5<br /><br />== 4 ==<br />A6 -- A5<br />A1 -- A4<br />A2 -- A3<br /><br />== 5 ==<br />A3 -- A6<br />A4 -- A2<br />A5 -- A1<br />这是单循环的
双循环将 14 行的
while($lun++ 改作
while($lun++ 就可以了
真难为了 贝格尔 弄出这么个编排法
绕了5、6个小时才把算法理顺

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