一个重大困惑难题，怎么有效防止CSRF攻击-PHP Tutorial-php.cn

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一个重大困惑难题，怎么有效防止CSRF攻击

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Jun 13, 2016 am 11:57 AM

ajaxhttpnbsprefererserver

一个重大困惑难题，如何有效防止CSRF攻击
网上有种方法是使用
$_SERVER['HTTP_REFERER']
但是有文章又指出
referer可以伪造的
例如
header("referer:www.aaa.com")
……
?>
我试了一下，貌似用header发送在控制台台里看到referer是变化了
但是$_SERVER['HTTP_REFERER']是空的，说明似乎没问题
那到底这个参数行不行呢？能不能防止呢？
------解决方案--------------------
CSRF通过伪装来自受信任用户的请求来利用受信任的网站

那么用 $_SERVER['HTTP_REFERER'] 显然是不可以的，因为这是可伪造的（你也是知道的）
对于表单，你可以放置一个即时发放的随机串（token）或验证码
对于普通页，你可以通过 ajax 获取一个通行字（因为 ajax 是不可跨域的，且模拟 js 行为技术难度较大）
你也可以通过页面中后期加载的对象（比如图片、js 文件）来传递附加的 cookie 变量
被动防御时，可过滤掉页面中非已知的连接

------解决方案--------------------
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