Home >Backend Development >PHP Tutorial >截取多个JSON的参数值遇到有关问题
截取多个JSON的参数值遇到有关问题
- WBOYOriginal
- 2016-06-13 11:54:45919browse
截取多个JSON的参数值遇到问题。
POST获取的JSON数据 [{"Name":"PM","Value":"224"},{"Name":"WD","Value":"25"},{"Name":"SD","Value":"34"},]
如何截取 Name＝WD 的Value？
求代码。
------解决方案--------------------
$json = '[{"Name":"PM","Value":"224"},{"Name":"WD","Value":"25"},{"Name":"SD","Value":"34"}]';<br />$jsonArr = json_decode($json) ;<br />foreach ($jsonArr as $value) {<br /> if($value->Name == 'WD'){<br /> echo $value->Value."<br />";<br /> }<br />}<br /><br />
Statement：
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Previous article：广州市PHP培训 最好的PHP培训机构Next article：PHP cli模式下提醒 Module 'xxx' already loaded