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接收到的json解析不了,必须用php解析,该如何解决

WBOY
WBOYOriginal
2016-06-13 11:42:511335browse

接收到的json解析不了,必须用php解析

<br />function sendPost($url,$postData){<br /> $postdata = http_build_query($postData);<br /> $options = array(<br /> 'http' => array(<br /> 'method' => 'POST',<br /> 'header' => 'Content-type:application/x-www-form-urlencoded',<br /> 'content' => $postdata,<br /> 'timeout' => 15 * 60 // 超时时间(单位:s)<br />)<br /> );<br /> $context = stream_context_create($options);<br /> $result = file_get_contents($url, false, $context);<br /><br /> return $result;<br /> }<br /><br /><br />$url = "http://chepiao.sinaapp.com/api.php?act=remain";<br />$data = array(<br /> "date"=>"20131220",<br /> "startStation"=>"北京",<br /> "arriveStation"=>"天津"<br />);<br />$result = sendPost($url, $data);<br /> $obj = json_decode($result);<br />$result就是返回来的数据,就是解析不了,用json_decode($result);解析成的是NULL

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