php获取当前网址url并替换参数
??? 没有使用ajax提交,就是最一般的提交的话,$_REQUEST[]就好了,但是如果是ajax加载也的form提交,而且想得到当前页面url中的某个参数的话,就必须使用$_SERVER['HTTP_REFERER'];然后对其进行处理这个用firefox查看refer就能知道原理了.
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