多个字符串找出不同点
假如我有如下字符串
(
[0] => http://news.qq.com/newsgn/zhxw/shizhengxinwen_2.htm
[1] => http://news.qq.com/newsgn/zhxw/shizhengxinwen_3.htm
[2] => http://news.qq.com/newsgn/zhxw/shizhengxinwen_4.htm
[3] => http://news.qq.com/newsgn/zhxw/shizhengxinwen_5.htm
[4] => http://news.qq.com/newsgn/zhxw/shizhengxinwen_80.htm
)
有什么好的算法可以得到他们的不同点,用(*)替代?
比如以上网址可以归纳为
http://news.qq.com/newsgn/zhxw/shizhengxinwen_(*).htm
------解决方案--------------------
算法需要建立在每组字符串都有某种相同的规律。
如果是 array('hello', 'hellp', 'world'); 怎么表示? (*)(*)(*)(*)(*) ?

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