php中mysql_query 返回值出错
$conn=mysql_connect("localhost","root","root") or die("链接数据库失败");
mysql_select_db("text");
$sql="SELECT * FROM mytext";
$query=mysql_query($sql);
if($query) //判断mysql_query是否成功返回
{
echo "true";
$num=mysql_fetch_array($query);
print_r($num);
echo $num[1];
}
else
echo "false";
?>
执行结:页面打印出 false
为什么$sql="SELECT * FROM mytext"这一句没有成功执行,数据库里的表都设有字段和值了??求大虾帮忙!!
------解决方案--------------------
$query=mysql_query($sql) or die(mysql_error());
这样报错了没有?
建议这样写规范点:
else{
echo "false";
}
------解决方案--------------------
数据库名是text?这是MySQL保留字哦,加反引号试试:
- PHP code
mysql_select_db("`text`");<div class="clear"> </div>

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