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The jquery formValidator plug-in ajax validation method leaves the error prompt without making any changes to the content_jquery

WBOY
WBOYOriginal
2016-05-16 17:44:32945browse

The query formValidator plug-in is very easy to use, but there is a serious bug. When using ajax verification, if the content of the input box already exists, put the mouse into the input box and leave without making any modifications, an error will be prompted. , This is a very stupid mistake made by this plug-in

Copy the code The code is as follows:

oneIsValid: function(id, index) {
var returnObj = new Object();
returnObj.id = id;
returnObj.ajax = -1;
returnObj.errormsg = ""; / /Customize error message
var elem = $("#" id).get(0);
var settings = elem.settings;
var settingslen = settings.length;
//Only When a formValidator is used, it is not checked
if (settingslen == 1) { settings[0].bind = false; }
if (!settings[0].bind) { return null; }
for ( var i = 0; i < settingslen; i ) {
if (i == 0) {
if ($.formValidator.isEmpty(id)) {
returnObj.isvalid = true;
returnObj.setting = settings[0];
break;
}
continue;
}
returnObj.setting = settings[i];
if (settings[i]. validatetype != "AjaxValidator") {
$.formValidator.triggerValidate(returnObj);
} else {
returnObj.ajax = i;

settings[i].isvalid = true;
}
if (!settings[i].isvalid) {
returnObj.isvalid = false;
returnObj.setting = settings[i];
break;
} else {
returnObj.isvalid = true;
returnObj.setting = settings[0];
if (settings[i].validatetype == "AjaxValidator") break;
}
}
return returnObj;
},
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