Home > Article > Backend Development > 效果的对比显示
求一个效果的对比显示
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2120844 DJ小罗Remix这该死的温柔DISCO
2120843 lucky_twice-魔法项链第一首-DJ-舞曲-慢摇
2120842 Beautiful_Girls_(DJ→梦←Extended_Remix)
2120841 DjRuico_FunkyHouse_Remix
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OKNDR1 DjRuico_FunkyHouse_Remix
DGERR2 lucky_twice-魔法项链第一首-DJ-舞曲-慢摇
EGDSF3 DJ小罗Remix这该死的温柔DISCO
EEEED4 Beautiful_Girls_(DJ→梦←Extended_Remix)
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要实现的效果为:
DJ小罗Remix这该死的温柔DISCO [a]2120844[/a] [bb]EGDSF3[/bb]
lucky_twice-魔法项链第一首-DJ-舞曲-慢摇 [a]2120843[/a][bb]DGERR2[/bb]
Beautiful_Girls_(DJ→梦←Extended_Remix) [a]2120842[/a][bb]EEEED4[/bb]
DjRuico_FunkyHouse_Remix [a]2120841[/a][bb]OKNDR1[/bb]
其实就是把,A和B记录对比,拿名称做一个唯一的对比,
我想到思路可不知道用什么代码做好。JS 还是ASP 还是PHP
------解决方案--------------------
$a = array( array('2120844', 'DJ小罗Remix这该死的温柔DISCO'), array('2120843', 'lucky_twice-魔法项链第一首-DJ-舞曲-慢摇'), array('2120842', 'Beautiful_Girls_(DJ→梦←Extended_Remix)'), array('2120841', 'DjRuico_FunkyHouse_Remix'),);$b = array( array('OKNDR1', 'DjRuico_FunkyHouse_Remix'), array('DGERR2', 'lucky_twice-魔法项链第一首-DJ-舞曲-慢摇'), array('EGDSF3', 'DJ小罗Remix这该死的温柔DISCO'), array('EEEED4', 'Beautiful_Girls_(DJ→梦←Extended_Remix)'),);$r = array();foreach($a as $v) $r[$v[1]][] = $v[0];foreach($b as $v) $r[$v[1]][] = $v[0];foreach($r as $k=>$v) echo "$k [a]$v[0][/a] [bb]$v[1][/bb]\n";<br><font color="#e78608">------解决方案--------------------</font><br>
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