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Why Are Floating-Point Calculations in C# Imprecise?

Mary-Kate Olsen
Mary-Kate OlsenOriginal
2025-01-31 04:18:08769browse

Why Are Floating-Point Calculations in C# Imprecise?

Understanding Floating-Point Imprecision in C#

Floating-point arithmetic's inherent imprecision often leads to unexpected results. Consider this C# code snippet:

<code class="language-csharp">class Program
{
    static void Main(string[] args)
    {
        float f1 = 0.09f * 100f;
        float f2 = 0.09f * 99.999999f;

        Console.WriteLine(f1 > f2); // Surprisingly prints "false"
    }
}</code>

The output, "false," is counterintuitive, as both calculations appear to yield 9.0. This discrepancy arises from the limitations of floating-point representation.

IEEE 754 standard floating-point numbers use a finite number of bits to represent fractional parts. This means many decimal values cannot be precisely stored; they are approximated. The values 0.09f and the results of the calculations are approximations. These approximations, while often insignificant, can cause unexpected comparisons.

Therefore, directly comparing floating-point numbers for equality (==) is unreliable. Instead, use a tolerance-based comparison:

<code class="language-csharp">Console.WriteLine(Math.Abs(f1 - f2) < 0.0001); // A more robust comparison</code>

This approach checks if the absolute difference between f1 and f2 is below a predefined threshold (0.0001 in this case). Adjust the threshold based on your application's required precision.

Alternatively, using double (double-precision floating-point numbers) offers higher precision than float (single-precision), reducing the likelihood of these inaccuracies. However, even double values are subject to similar limitations, albeit with a smaller margin of error. Careful consideration of precision requirements is essential for reliable floating-point computations.

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