Why Does `a = b` Work While `a = a b` Fails When `a` and `b` are `short` in C#?

C# short Arithmetic: A Subtlety

Adding two short variables in C# directly, like this:

short a, b;
a = 10;
b = 10;
a = a + b; // Error: Cannot implicitly convert type 'int' to 'short'

produces a compiler error. The reason? The sum of two short values is implicitly promoted to an int. Assigning an int to a short variable requires an explicit cast, which is missing in this code.

Surprisingly, the compound assignment operator = works without error:

a += b; // Works correctly

Why the difference?

The = Operator's Secret

The = operator isn't simply syntactic sugar; it's a carefully designed language feature. While functionally equivalent to a = a b, the compiler treats it differently. The C# specification dictates that compound assignment operators perform an implicit conversion from the result of the operation to the type of the left-hand operand.

In essence, a = b is implicitly handled as a = (short)(a b). The compiler automatically inserts the necessary cast to short, preventing the type mismatch error.

This implicit casting is a crucial aspect of C#'s design. Without it, many common arithmetic operations involving smaller integer types would necessitate explicit casting, adding significant complexity to the code.

In Short (Pun Intended)

The core issue is the implicit type promotion of short short to int. The = operator cleverly circumvents this by incorporating an implicit cast, making it a convenient and efficient way to perform arithmetic operations on smaller integer types without explicit type conversions.

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