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How Can LINQ Efficiently Filter Items in One List Based on the Presence of Items in Another List?

Barbara Streisand
Barbara StreisandOriginal
2025-01-19 18:27:10246browse

How Can LINQ Efficiently Filter Items in One List Based on the Presence of Items in Another List?

Use LINQ query to filter items in the list

LINQ provides an efficient way to filter items in a list based on whether the item exists in another list. Please see the code example below:

<code class="language-csharp">class Program
{
    static void Main(string[] args)
    {
        // 示例数据
        List<Person> peopleList1 = new List<Person>() { new Person() { ID = 1 }, new Person() { ID = 2 }, new Person() { ID = 3 } };
        List<Person> peopleList2 = new List<Person>() { new Person() { ID = 1 }, new Person() { ID = 2 }, new Person() { ID = 3 }, new Person() { ID = 4 }, new Person() { ID = 5 } };
    }
}

class Person
{
    public int ID { get; set; }
}</code>

We need to find the items in peopleList2 that are not in peopleList1. This can be achieved via LINQ.

Use the Except() method

LINQ provides the Except() method, which returns all elements in the first list that are not in the second list. We can use it as follows:

<code class="language-csharp">var result = peopleList2.Except(peopleList1);</code>

This will return a collection containing people with IDs 4 and 5.

Use LINQ query syntax

LINQ also allows us to perform filtering operations using query syntax. Here's one way to achieve the same result using query syntax:

<code class="language-csharp">var result = from p in peopleList2
             where !peopleList1.Any(p2 => p2.ID == p.ID)
             select p;</code>

This query produces the same results as the Except() method.

Performance Description:

It should be noted that the time complexity of both methods is O(n*m), where n and m are the sizes of the two lists being compared. This means that as the size of the list grows, the time required for the filtering operation increases significantly. For large data sets, other methods may need to be explored to optimize performance.

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