Home >Backend Development >C++ >Can C# Generic Constructors Enforce Specific Parameter Types Beyond Parameterless Constructors?
In C#, constraints can be placed on generic methods to ensure that specific requirements are met. A common constraint is to specify that a generic type must have a parameterless constructor. However, a natural question arises: can we impose more specific constraints on the constructor?
Let's take the example provided in the question, where we want to force a constructor that accepts a float[,] parameter. Initial attempt:
<code class="language-c#">public static T Method<T>(T a) where T : new(float[,] u) { //...do something... return new T(new float[0, 0]); }</code>
Compilation failed, forcing us to look for alternatives.
To circumvent this limitation, we adopted a workaround by introducing a delegate responsible for creating instances of type T. This delegate takes the necessary parameters as parameters and returns an instance of T.
<code class="language-c#">public static void Method<T>(T a, Func<float[,], T> creator) { //...do something... }</code>
Modify our code to use this delegate, with the following results:
<code class="language-c#">A.Method(float[,], instanceCreator); Func<float[,], T> instanceCreator = (float[,] arr) => new T(arr);</code>
This solution allows us to impose more complex constraints on the constructor by passing in a suitable delegate.
The above is the detailed content of Can C# Generic Constructors Enforce Specific Parameter Types Beyond Parameterless Constructors?. For more information, please follow other related articles on the PHP Chinese website!