Find consecutively numbered gaps in MySQL
In this query, the poster encountered missing values in an auto-increment column of a table, although there were no duplicates. The goal of the problem is to identify and return the values of missing numbers, which may not be consecutive, such as ids 71-82.
Better solution
JustPlainMJS offers an alternative that significantly improves performance.
Less efficient solution
For tables of any size, consider the following approach:
SELECT (t1.id + 1) as gap_starts_at, ( SELECT MIN(t3.id) -1 FROM arrc_vouchers t3 WHERE t3.id > t1.id ) as gap_ends_at FROM arrc_vouchers t1 WHERE NOT EXISTS ( SELECT t2.id FROM arrc_vouchers t2 WHERE t2.id = t1.id + 1 ) HAVING gap_ends_at IS NOT NULL
In this query:
-
gap_starts_at
represents the first id in the current gap. -
gap_ends_at
represents the last id in the current gap.
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