Why Does `System.out.println()` Print a Strange Output When Displaying a Java Array, and How Can I Correctly Print Its Elements?

Arrays in Java: Unraveling Mysterious Output and Printing Array Elements

Java arrays provide a convenient way to store and manipulate collections of elements of the same type. However, when printing an array using System.out.println(), you may encounter unexpected output.

Consider the following code snippet:

int[] arr = new int[5];

arr[0] = 20;
arr[1] = 50;
arr[2] = 40;
arr[3] = 60;
arr[4] = 100;

System.out.println(arr);

When executed, this code will produce output similar to "[I@3e25a5". This output represents the object's class name ("[I") followed by the array's address in memory ("3e25a5").

To display the actual elements of the array, you can use either of the following techniques:

1. Java.util.Arrays.toString():

   System.out.println(java.util.Arrays.toString(arr));

   This utility method returns a string representation of the array, enclosing the elements within square brackets.

2. Looping Through the Array:

   for (int i = 0; i < arr.length; i++) {
       System.out.println(arr[i]);
   }

   This loop iterates through the array, printing each element on a separate line.

By utilizing these techniques, you can obtain the desired output, representing the exact numbers from the array.

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