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Q: Is it possible to write a CSS selector that selects elements that don't have a particular class or attribute?
In most cases, it's feasible with the :not() pseudo-class. For instance, given the HTML below, a selector can be written to select all elements that lack the "printable" class:
<html>
A: To select the elements without the "printable" class in this case (i.e., the nav and a elements), use the following selector:
:not(.printable) { /* Styles */ }
For CSS attributes, the syntax is similar:
:not([attribute]) { /* Styles */ }
Considerations for IE8 and Earlier: Note that IE8 and earlier don't support :not(). As a workaround, consider styling elements that do have the "printable" class instead. If this approach is impractical, you may need to modify your markup to accommodate the limitation.
Caution: Depending on the properties applied, using :not() can impact descendant elements in unexpected ways. For instance, setting display: none on :not(.printable) will remove the element and its subtree from the layout, affecting even descendant elements that do have the "printable" class. Use caution when applying potentially problematic properties and consider using visibility: hidden instead.
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