How to Generate a Class from a Database Table in SQL Server
Creating simple entities as classes from SQL Server table objects is possible without using ORM. This method provides a straightforward way to generate class structures that align with the table schema.
Steps:
- Set Table Name: Declare a variable @TableName to hold the name of the target table.
- Generate Class Structure: Construct a string @Result with the starting bracket and class name based on the table name.
- Iterate Over Columns: Retrieve column information (name, data type, nullability) from the sys.columns and sys.types system tables, filtered by the object_id of the target table.
- Build Class Properties: For each column, append a class property declaration to @Result. Properties include the column name, data type, and optional nullable character (?) if the column allows null values. Data types are converted to C# equivalents for compatibility.
- Generate Class Code: Complete the class structure with a closing bracket and print the resulting code. This provides a C# class that mirrors the schema of the specified table.
Example:
Consider a table named "Person" with columns "Name" (string) and "Phone" (nullable string):
declare @TableName sysname = 'Person' declare @Result varchar(max) = 'public class ' + @TableName + ' {' select @Result = @Result + ' public ' + ColumnType + NullableSign + ' ' + ColumnName + ' { get; set; } ' from ( select replace(col.name, ' ', '_') ColumnName, column_id ColumnId, case typ.name when 'varchar' then 'string' else 'UNKNOWN_' + typ.name end ColumnType, case when col.is_nullable = 1 and typ.name = 'varchar' then '?' else '' end NullableSign from sys.columns col join sys.types typ on col.system_type_id = typ.system_type_id AND col.user_type_id = typ.user_type_id where object_id = object_id(@TableName) ) t order by ColumnId set @Result = @Result + ' }' print @Result
Output:
public class Person { public string Name { get; set; } public string? Phone { get; set; } }
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