Validate Decimal Numbers in JavaScript: IsNumeric()
Problem Statement:
Determine the most effective and clear method for validating decimal numbers in JavaScript, ensuring cross-platform compatibility.
Test Cases:
- IsNumeric('-1') → true
- IsNumeric('-1.5') → true
- IsNumeric('0') → true
- IsNumeric('0.42') → true
- IsNumeric('.42') → true
- IsNumeric('99,999') → false
- IsNumeric('0x89f') → false
- IsNumeric('#abcdef') → false
- IsNumeric('1.2.3') → false
- IsNumeric('') → false
- IsNumeric('blah') → false
Solution:
To achieve universal numeric validation, regardless of data type, a combination of isNaN and isFinite is recommended:
function isNumeric(n) {
return !isNaN(parseFloat(n)) && isFinite(n);
}
This code effectively coerces any input into a number and checks for validity and finiteness. However, it's important to note that it will also consider hexadecimal and exponential formats as numeric.
Additional Approaches:
-
jQuery's isNumeric: Compares the original input string with its floating-point representation to determine if they differ by less than 1.
-
Angular 4.3 isNumeric: Subtracts the value from its floating-point representation and checks for a non-NaN result.
Considerations:
- Utilize Number.isNaN and Number.isFinite in ES6 for improved type conversion handling.
- The provided solution treats all numeric values as valid, including hexadecimal and exponential formats. Adjust the implementation based on specific validation requirements.
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