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How Can I Concatenate a std::string and an Integer in C ?

Barbara Streisand
Barbara StreisandOriginal
2024-12-24 01:43:14594browse

How Can I Concatenate a std::string and an Integer in C  ?

Concatenating a std::string and an int

Combining a std::string and an int to form a single string can be a straightforward task. Here are multiple approaches to achieve this:

1. Using Boost

#include <boost/lexical_cast.hpp>

std::string name = "John";
int age = 21;

std::string result = name + boost::lexical_cast<std::string>(age);

2. Using C 11

std::string name = "John";
int age = 21;

std::string result = name + std::to_string(age);

3. Using FastFormat

#include <fastformat/format.hpp>

std::string name = "John";
int age = 21;

std::string result;
fastformat::fmt(result, "{0}{1}", name, age); // FastFormat.Format
fastformat::write(result, name, age); // FastFormat.Write

4. Using the {fmt} library

#include <fmt/core.h>

std::string name = "John";
int age = 21;

std::string result = fmt::format("{}{}", name, age);

5. Using IOStreams

std::string name = "John";
int age = 21;

std::stringstream sstm;
sstm << name << age;
std::string result = sstm.str();

6. Using itoa

std::string name = "John";
int age = 21;

char numstr[21]; // enough to hold all numbers up to 64-bits
std::string result = name + itoa(age, numstr, 10);

7. Using sprintf

std::string name = "John";
int age = 21;

char numstr[21]; // enough to hold all numbers up to 64-bits
sprintf(numstr, "%d", age);
std::string result = name + numstr;

8. Using STLSoft's integer_to_string

#include <stlsoft/integer_to_string.hpp>

std::string name = "John";
int age = 21;

char numstr[21]; // enough to hold all numbers up to 64-bits
std::string result = name + stlsoft::integer_to_string(numstr, 21, age);

9. Using STLSoft's winstl::int_to_string()

#include <stlsoft/winstl/int_to_string.hpp>

std::string name = "John";
int age = 21;

std::string result = name + winstl::int_to_string(age);

10. Using Poco NumberFormatter

#include <Poco/NumberFormatter.h>

std::string name = "John";
int age = 21;

std::string result = name + Poco::NumberFormatter().format(age);

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