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Understanding the Weirdness of Integer Boxing in Java
In Java, primitive data types like integers have corresponding wrapper classes, such as Integer, to provide object-oriented functionality. How these values are boxed and unboxed can lead to surprising results.
One such observation comes from the following code:
public class WeirdBoxing { public static void main(String[] args) { Integer a = 1000, b = 1000; System.out.println(a == b); Integer c = 100, d = 100; System.out.println(c == d); } }
When executed, this code prints:
false true
Why does the first comparison return false while the second returns true? According to the == operator, references should always be compared.
The Mystery Behind the "True" Comparison
Interestingly, the true comparison is not a fluke. Java Language Specification (JLS) Section 5.1.7 states:
If the value p being boxed is [...] an int or short number between -128 and 127, [...] then let r1 and r2 be the results of any two boxing conversions of p. It is always the case that r1 == r2.
In this instance, c and d both hold values within the specified range, causing their boxed representations (Integer objects) to be identical.
The Ambiguity of Non-Fixed-Range Comparisons
In contrast, the first comparison (a == b) does not fall under the guaranteed equality rule. The JLS emphasizes this:
For other values, [the rules] disallows any assumptions about the identity of the boxed values on the programmer's part.
Essentially, when boxing values outside the fixed range, there's no guarantee of identical references.
Conclusion
The strange behavior of Integer boxing in Java stems from the language specification's provision for efficiency and common use cases. While values within a certain range are guaranteed to be boxed identically, for other values, the identity of the boxed objects is unpredictable. This understanding illuminates the "weirdness" exemplified by the code snippet presented at the outset.
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