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Can Pointers in Struct Pointer Methods Be Reassigned in Golang?
In Golang, struct pointer methods allow modifications to be made to the receiver struct without the need to explicitly pass a pointer. However, many developers encounter difficulty when attempting to reassign the primary pointer within a struct pointer method.
One particular scenario involves the AVL tree, where the tree.rotateLeftToRoot() method does not update the tree pointer outside the scope of the function. This has led to the question of能否在函数作用域外重新分配结构指针方法中的指针,或是否不鼓励这样做?
Understanding Pointers and Values
Pointers in Golang represent memory addresses, while other data types (such as integers) represent their own values. When modifying variables of type *T (where T is any data type), it is necessary to pass a pointer to that variable (**T). This allows for modifying the pointed object (the value at the memory address) rather than just the copy of the pointer.
Limitations of Receiver Types
In the case of struct pointer methods, the receiver cannot be a pointer of a pointer (**T). This means that the pointer within a struct pointer method cannot be directly reassigned.
Solutions to Reassignment
There are two possible solutions:
Example Implementations
Non-Pointer Function:
func rotateLeftToRoot(ptree **AvlTree) { tree := *ptree if tree == nil { return } prevLeft := tree.left if prevLeft != nil { tree.left = prevLeft.right prevLeft.right = tree tree = prevLeft } *ptree = tree }
Method with Returned Pointer:
func (tree *AvlTree) rotateLeftToRoot() *AvlTree { if tree == nil { return nil } prevLeft := tree.left if prevLeft != nil { tree.left = prevLeft.right prevLeft.right = tree tree = prevLeft } return tree }
In either case, the desired effect can be achieved. However, it is important to note that returning the pointer from a method is common practice, especially when modifications to the underlying data structure are made.
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