How Can I Overload the

Overriding Operator

This discussion centers around the challenge of overloading operator

The Problem:

When overloading operator

The Solution: Understanding Function Pointers

The key to resolving this issue lies in recognizing that std::endl is a function. The std::cout stream utilizes operator

Customizing Endline Manipulation for MyStream

To achieve similar functionality for my_stream, a specialized endl function can be defined with the following signature:

typedef MyStream& endl(MyStream& stream)

Within this function, you can perform any additional actions or modifications required for your specific stream implementation, ensuring that it behaves as intended when std::endl is used.

Overloading Operator

To allow my_stream to accept std::endl as well, declare another operator

typedef std::basic_ostream<char std::char_traits> > CoutType;
typedef CoutType& (*StandardEndLine)(CoutType&);

MyStream& operator<p>This operator calls std::endl on the standard output stream, mimicking the behavior of std::cout, while being compatible with my_stream's custom endl implementation.</p></char>

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