How to Prevent `java.lang.NumberFormatException` When Parsing Non-Integer Strings in Java?

Preventing java.lang.NumberFormatException for Non-Integer String Input

While encountering a java.lang.NumberFormatException with the message "For input string: "N/A"", it indicates that you are attempting to parse a string that does not represent a valid integer into an integer value. The string "N/A" in this case is not an integer.

Solution:

There are two approaches to prevent this exception:

Exception Handling:

Use try-catch block to handle the NumberFormatException and take appropriate action in case of a non-integer string:

try {
    int i = Integer.parseInt(input);
} catch (NumberFormatException ex) {
    // Handle the exception here, e.g., print an error message or replace the non-integer value with a default value.
}

Integer Pattern Matching:

Validate the input string using a regular expression before parsing it to an integer:

String pattern = "-?\d+";
if (input.matches(pattern)) { // Checks if the string matches the pattern of an integer (including negative values)
    int i = Integer.parseInt(input);
} else {
    // The input string is not an integer. Handle it appropriately.
}

By implementing either of these approaches, you can ensure that only valid integer strings are parsed into integers, preventing the occurrence of the java.lang.NumberFormatException.

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